All categories

3 years ago

quadrilateral ABCD is a parallelogram with diagonals that intersect at point E. Which of the following statements is true?

Mathematics

2 answers:

frez [133]3 years ago

8 0

Statement D because A and C are equidistant from the point E (they have the same distance to point E) so AE _~ CE

krok68 [10]3 years ago

7 0

Answer:

The answer is (D) ⇒ AE ≅ CE

Step-by-step explanation:

∵ ABCD is a parallelogram

∴ AB = DC , AB // DC

∴ BC = AD , BC // AD

∴ m∠A = m∠C , m∠B = m∠D

∴ AC and BD bisect each other at E

∴ AE = CE

∴ The right statement is D ⇒ AE ≅ CE

You might be interested in

Please help me! i will give 10 points and brainliest to those who show their work!!

Black_prince [1.1K]

Hopefully this helps.

8 0

3 years ago

Ane goes to a juice bar with her friend neil. she is thinking of ordering her favorite drink, 7/8 orange juice and 1/8 cranberry

Aleksandr-060686 [28]

Jcbldbasjvbl bd.kfjv ,m s,j zdf, f,kbnkfeanbvile

3 0

3 years ago

Find the midpoint of the segment whose endpoints are (8,6) and (-2,-8).

inna [77]

Answer:

$\huge{ \fbox{ \sf{ \: ( \: 3 \: , \: - 1 \: )}}}$

Step-by-step explanation:

$\star{ \sf { \: Let \: the \: points \:be \: A \: and \: B}}$

$\star{ \sf{ \: Let \: \: A (8,6) \: be \: (x1 \:, y1) and \: B(-2,-8) \: be \: (x2 \:, y2)}}$

$\underline{ \sf{Finding \: the \: midpoint}}$

$\boxed{ \rm{Midpoint \: = \: ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{8 + ( - 2)}{2} \: , \: \frac{6 + ( - 8)}{2} )}}$

$\mapsto { \sf{Midpoint = ( \frac{8 - 2}{2} \: , \: \frac{6 - 8}{2} }})$

$\mapsto{ \sf{Midpoint = ( \frac{6}{2} \: , \: \frac{ - 2}{2}) }}$

$\mapsto{ \sf{Midpoint = (3 \: \: , - 1)}}$

Hope I helped!

Best wishes!! :D

~ $\sf{TheAnimeGirl}$

5 0

3 years ago

Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays

katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

Answer: The half life of the sample of phosphorus-32 is $14.28days^{-1}$

Step-by-step explanation:

The equation used to calculate the half life of the sample is given as:

$m(t)=m_o(1/2)^{t/h}$

where,

m(t) = amount of sample after time 't' = 356 g

$m_o$ = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

$356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}$

Hence, the half life of the sample of phosphorus-32 is $14.28days^{-1}$

7 0

3 years ago

Show your work. Round to the nearest cent when necessary.

hjlf

Answer:

Option A

Step-by-step explanation:

Bag A: 30 cents per bag

Bag B: 31 cents per bag

In order to find Cents per bag divide the number of bags from the amount it costs.

Bag A: 6 ÷ 20 = 0.30

Bag B: 9.92 ÷ 32 = 0.31

3 0

2 years ago

Read 2 more answers