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Kay [80]
3 years ago
13

- 7s+12=-9s what is the answer

Mathematics
2 answers:
Flura [38]3 years ago
7 0
The same variable can not be on both sides of the equation.

Add 7s to both sides so that the variable is only on he right side.

12=-2s

Divide each side by -2

s=-6

To check your answer, substitute -6 in for s

-7(-6)+12=-9(-6)
42+12=54
54=54

s=-6

Hope this helped! Tell me if you want me to help with anything else or explain this in a different way :)
weqwewe [10]3 years ago
6 0
12=-9s+7s
12=-2s
-6=s
Hope this helps
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Write a rule/equation for each of the lines shown!!!!
Fofino [41]

For the line that has a positive slope, the equation is y = 2x - 1

This is because slope is rise over run(rise/run) or m = y₂-y₁ / x₂-x₁. The line goes up(rise) 2 units, and goes to the right(run) by 1 unit.

The y-intercept(the point the line touches when x = 0) is -1.

You use the equation y = mx + b, try to find m and b(y-intercept) and plug it into the equation.


For the line that has a negative slope, the equation is y = -x + 5

8 0
3 years ago
You make a salary of $400 a month plus a 10% commission. If your total sales were $2000, how much money in total would you make
kykrilka [37]

Given:

Salary = $400 a month

Rate of commission = 10%

Total sales = $2000

To find:

The total money you will make this month.

Solution:

We have,

Rate of commission = 10%

Total sales = $2000

Commission = 2000\times \dfrac{10}{100}

                    = 200

We know that,

Total money = Salary + Commission

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                     = \$600

Therefore, the total money you will make this month is $600.

3 0
3 years ago
A manufacturer produces bolts of a fabric with a fixed width. The quantity q of this fabric (measured in yards) that is sold is
slamgirl [31]

Answer:

(A) the selling price is $20 per yards, and the expected yards to be sold is 10,000 yards

the derivative f'(20) is negative, which means the fabric producing company will sell 350 fewer yards when selling price is $20 per yard

(B) = R'(20) = $3000

∴the company will get extra $3000 revenue when selling price is $20 per yard

Step-by-step explanation:

A. given that

<em>f</em>(20)= 10,000

<em>f'</em>(20)= -350(first derivative)

the selling price is $20 per yards, and the expected yards to be sold is 10,000 yards

the derivative f'(20) is negative, which means the higher the price, it wil reduce the number of yards to be sold making it 350 fewer yards

(B) R(p) = p <em>f</em>(p)

<em>f</em>(20)= 10,000

<em>f'</em>(20)= -350(first derivative)

R(p) = p <em>f</em>(p)

differentiate with respect to p, using product rule

R'(p) = p <em>f' </em>(p) + <em>f</em>(p) (first derivative)

where p = 20

R'(20) = 20 <em>f' </em>(20) + <em>f</em>(20)

R'(20) = 20(-350) + 10,000

R'(20) = -7000 + 10,000

R'(20) = $3000

∴ the revenue is increasing by $3000 for every selling sold yard and increase in price per yard

3 0
3 years ago
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chubhunter [2.5K]

hello

to solve this question, we need to use know the number of possible outcomes

\begin{gathered} \text{probability = }\frac{nX}{nS} \\ S=\text{  number of possible outcomes} \\ X=\text{ number of events} \end{gathered}

let's find the number of possible outcomes

we have four tiles numbered 1, 4, 5 and 8

possible outcomes are

undefined

5 0
1 year ago
Mike went shopping at the Nike outlet in Rehoboth Beach, DE. There is no additional sales tax in the state of Delaware. He bough
Dahasolnce [82]

Answer:

$25 each pair of shorts

Step-by-step explanation:

5(15)+2x=125

2x=50

x = 25

8 0
3 years ago
Read 2 more answers
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