Answer:
The price of pretzels in 1975 = $1.80
Step-by-step explanation:
To answer this question we are assuming the steady rate means linear.Let x be the year and y be the price.
We need to find the slope
m = (y2-y1)/(x2-x1)
= (4.80-4.05)/(2015-2005)
=.75/10
= .075
The slope is .075
We can use the point slope form of the equation
y-y1 = m(x-x1)
y-4.80 = .075(x-2015)
Distribute
y - 4.80 = .075x -151.125
Add 4.80 to each side
y - 4.80+4.80 = .075x -151.125+4.80
y = .075 x - 146.325
We want to find out how much pretzels were in 1975. Put in x=1975
y = .075(1975) -146.325
y = 148.125-146.325
y=1.80
The problem ask to calculate the corresponding distance on the new patio where as the the patio will have two long parallel side and an area of 360 square feet and the area of the similar patio is 250 square feet and its long parallel sides are 12.5 feet apart. To calculate this the ratio of the distance of the two polygon is P:Q so it means that the are is also P^2:Q^2 so the ratio of the area is 36:25 so the the distance of the new patio is 18 feet
7:50 am
60 minutes before 8:40 would be 7:40 so 10 minutes after that would be 7:50
Answer:
A
Step-by-step explanation:
There are only three possible draws, however, some are more likely.