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azamat
3 years ago
5

For the given expression, use the Commutative Property of Addition to enter an equivalent expression.

Mathematics
1 answer:
Triss [41]3 years ago
3 0

Answer:

x+19=19+x

Step-by-step explanation:

You might be interested in
HELP PLEASE
Maurinko [17]
\bf \cfrac{x^2-x-42}{x-6}\implies \cfrac{(x+7)\underline{(x-6)}}{\underline{x-6}}\implies x+7

so.. the left-hand-side does indeed simplify to x+7, so the equation does check out.

however, notice something, for the equation of x+7, when x = 6, we get (6) + 7 which is 13.

BUT for the rational, we get    \bf \cfrac{x^2-x-42}{x-6}\qquad \boxed{x=6}\implies \cfrac{x^2-x-42}{\boxed{6}-6}\implies \stackrel{und efined}{\cfrac{x^2-x-42}{0}}

so, even though the siimplification is correct, the rational or original expression is constrained in its domain.
6 0
3 years ago
The Nisbets went through the drive through
Alexandra [31]

Answer:

One cup of coffee is $3.25

Step-by-step explanation:

Create a system of equations where c is the cost of a cup of coffee and d is the cost of a donut

2c + 4d = 10.5

c + 5d = 8.25

Solve by elimination by multiplying the top equation by -5 and the bottom equation by 4

-10c - 20d = -52.5

4c + 20d = 33

Add them together and solve for c

-6c = -19.5

c = 3.25

So, a cup of coffee is $3.25

8 0
3 years ago
-7 (5y - 2u - 5)<br> Use the distributive property to remove parentheses
Montano1993 [528]
Times -7 by everything in the parentheses. so

-7 times 5y=-35y
-7 times -2u=14u
-7 times -5 = 35

therefore 35y+14u+35
8 0
3 years ago
Calcula en cada caso las restantes razones trigonométricas de un angulo agudo si se conoce que:
olchik [2.2K]
A) cos a = (√22)/5; tan a = (√66)/22
B) sin a = (2√2)/3; tan a = 2√2
C) sin a = (√30)/6; cos a = (√6)/6
D) sin a = 3/5; tan a = 3/4
E) sin a = (5√26)/26; cos a = (√26)/26
F) sin a = 3/5; tan a = 3/4

Explanation
The ratio for sine is opposite/hypotenuse.  This means the side opposite the angle is √3 and the hypotenuse is 5.  Using the Pythagorean theorem to find the adjacent side,
(√3)² + A² = 5²
3+A² = 25
A² = 22
A=√22
This means that cos a = adjacent/hypotenuse = (√22)/5 and tan a = opposite/adjacent = (√3)/(√22) = (√66)/22.
B)  The ratio for cosine is adjacent/hypotenuse; this means the side adjacent to the angle is 1 and the hypotenuse is 3.  Using the Pythagorean theorem to find the side opposite the angle (p),
1² + p² = 3²
1+p² = 9
p² = 8
p=√8 = 2√2
This means that sin a = opposite/hypotenuse = (2√2)/3 and tan a = opposite/adjacent = (2√2)/1 = 2√2.
C) The ratio for tangent is opposite/adjacent; this means that the side opposite the angle is √5 and the side adjacent the angle is 1.  Using the Pythagorean theorem to find the hypotenuse,
(√5)²+1² = H²
5+1=H²
6=H²
√6 = H
This means that sin a = opposite/hypotenuse = (√5)/(√6) = (√30)/6 and cos a = adjacent/hypotenuse = 1/(√6) = (√6)/6.
D)  The ratio for cosine is adjacent/hypotenuse; this means that the side adjacent the angle is 4 and the hypotenuse is 5.  Using the Pythagorean theorem to find the side opposite the angle, p:
4²+p²=5²
16+p²=25
p²=9
p=3
This means that sin a = opposite/hypotenuse = 3/5 and tan a = opposite/adjacent = 3/4.
E)  The ratio for tangent is opposite/adjacent;; this means that the side opposite the angle is 5 and the side adjacent the angle is 1.  Using the Pythagorean theorem to find the hypotenuse,
5²+1²=H²
25+1=H²
26=H²
√26 = H
This means that sin a = opposite/hypotenuse = 5/(√26) = (5√26)/26 and cos a = adjacent/hypotenuse = 1/(√26) = √26/26.
F) 0.8 = 8/10; The ratio for cosine is adjacent/hypotenuse.  This means that the side adjacent the angle is 8 and the hypotenuse is 10.  Using the Pythagorean theorem to find the side opposite the angle, p:
8²+p² = 10²
64+p² = 100
p² = 36
p=6
This means that sin a = opposite/hypotenuse = 6/10 = 3/5 and tan a = opposite/adjacent = 6/8 = 3/4.
6 0
3 years ago
Read 2 more answers
Subtract the cube root of the product of h and 3k from the square of the sum of p and q​
ehidna [41]

Answer:

(p + q)²            -          ∛(h·3k)   or   (p + q)² - ∛(h·3k)  

Step-by-step explanation:

Cube root of x:  ∛x

Product of h and 3k:  h·3k

Sum of p and q:  p + q

*****************************

From (p + q)²      subtract ∛(h·3k)      This becomes, symbolically:

=>       (p + q)²            -          ∛(h·3k)

3 0
3 years ago
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