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Levart [38]
2 years ago
7

A cookie delivery company charges $0.90 per cookie plus a $3 delivery fee. If an

Mathematics
1 answer:
ss7ja [257]2 years ago
6 0

Answer:

9 cookies

Step-by-step explanation:

The equation is 11.1 = 0.9x + 3. First, we need to isolate the variable so we subtract 3 from both sides. 8.1 = 0.9x. Next we divide both sides by 0.9 which gives us 9 = x or x = 9.

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Show work. This is a BC calculus problem.
stepan [7]

Answer:

D.

Step-by-step explanation:

Remember that the limit definition of a derivative at a point is:

\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}

Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:

\displaystyle{\frac{d}{dx}[f(1)]= \lim_{x \to 1}\frac{\ln(x+1)-\ln(2)}{x-1}}

Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).

The answer will thus be D.

5 0
2 years ago
(English to algebra) twice K is the same as three times k plus one
ryzh [129]

2k = 3k + 1



BTW k = -1

7 0
3 years ago
Read 2 more answers
Which pair of triangles can be proven by congruent SAS? HELP ASAP
Y_Kistochka [10]
The first one since the given measurements/guide is Side, Angle, Side
7 0
3 years ago
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You have the choice of logging on at one of two Internet cafés. Their posted rates are as follows: Log-On Café: $5.50 plus $0.15
erastovalidia [21]
1. 5.50 + 0.15 * 45 = 12.25

2. 4 + 0.20 * 45 = 13

So the first option is slightly better, you can save 13-12.25= $0.75.
4 0
3 years ago
calcula el área lateral de un prisma cuya base es un pentagono de 10cm de arista, 16.88 cm de apotema y 15 cm de altura
Romashka-Z-Leto [24]

Answer:

Lateral surface area of pentagonal prism = 750 cm²

Step-by-step explanation:

Given information:

Height of pentagonal prism = 15 cm

Length of edge = 10 cm

Length of apothem = 16.8 cm

Find:

Lateral surface area of pentagonal prism

Computation:

Lateral surface area of pentagonal prism = 5(a)(h)

Lateral surface area of pentagonal prism = 5(10)(15)

Lateral surface area of pentagonal prism = 750 cm²

5 0
2 years ago
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