Answer:
1. As definition, in a function, the set of all possible inputs or possible x values is called the domain.
=> Option 2 is correct.
2. As definition, in a function, the set of all possible outputs or possible y values is called the range.
=> Option 3 is correct.
3. You pay a fixed amount of 70$ and 3$ for each movie.
=> A function that models the total cost: y = 70 + 3x
=> Option 1 is correct
4. Similar to the 3rd, you pay a fixed amount of 5$ to enter and 2$ for each ride.
=> A function that models the total cost: y = 5 + 2x
=> Option 3 is correct.
5. The average rate of change (R) of f(x) = x2 + 1 from x = 0 to x = 3 is actually the rate of change of line passes (0, 1) and (3, 10) as shown in picture.
=> R = (10 - 1)/(3 - 0) = 9/3 = 3
=> Option 1 is correct.
6. As property of vertical line: 75 = x - 10 + 20
=> x = 75 + 10 - 20 = 65 deg
As property of complement angles: 75 + y = 180
=> y = 180 - 75 = 105 deg
=> Option 2 is correct.
7. Yes, the two triangles are congruent (Side-Angle-Side case) with two sides are equal and the pair of angles created by those pair of 2 sides are also equal.
Hope this helps!
:)
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
Donna borrowed $10,500 at a simple interest rate of 4% for 3 years to buy her new car. How much interest would Donna pay and how much is the car altogether ?
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
Principal (P) = $10,500
Rate of interest (r) = 4%
Time (t) = 3 years
<h3>To Find:-</h3>
Interest of Donna and amount of car altogether.
<h2>Solution:-</h2>
We know,

I = 
I = 
I = $1260
Now,
Amount of the car = $ (10,500 + 1260)
= $ 11,760
<h3><u>$</u><u>1</u><u>2</u><u>6</u><u>0</u> interest would Donna pay and <u>$</u><u>1</u><u>1</u><u>,</u><u>7</u><u>6</u><u>0</u> is the car altogether. [Answer]</h3>
Umm, I think it is the first one.
Answer:
80
Step-by-step explanation:
Answer:
Expression 2b+b and 3b have same values for all values of b.
Step-by-step explanation:
Given the two expression
and
and values of b as 1, 2 and 3.
Consider first expression that is,
.
Substituting the value of
,
....1
Substituting the value of
,
....2
Substituting the value of
,
....3
Consider second expression that is,
.
Substituting the value of
,
....4
Substituting the value of
,
....5
Substituting the value of
,
....6
For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.
Therefore both expression are same for all values of b.