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Musya8 [376]
3 years ago
7

How do you find the r?

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0
Use the formula (zy)i<span> = (y</span>i<span> – ȳ) / s </span>y<span> and calculate a standardized value for each y</span>i<span>. Add the products from the last step together. Divide the sum from the previous step by n – 1, where n is the total number of points in our set of paired data. The result of all of this is the correlation coefficient </span>r<span>.</span>
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Please, help! Pretty urgent!
jekas [21]

Answer:

1. As definition, in a function, the set of all possible inputs or possible x values is called the domain.

=> Option 2 is correct.

2. As definition, in a function, the set of all possible outputs or possible y values is called the range.

=> Option 3 is correct.

3. You pay a fixed amount of 70$ and 3$ for each movie.

=> A function that models the total cost: y = 70 + 3x

=> Option 1 is correct

4. Similar to the 3rd, you pay a fixed amount of 5$ to enter and 2$ for each ride.

=> A function that models the total cost: y = 5 + 2x

=> Option 3 is correct.

5.  The average rate of change (R) of f(x) = x2 + 1 from x = 0 to x = 3 is actually the rate of change of line passes (0, 1) and (3, 10) as shown in picture.

=> R = (10 - 1)/(3 - 0) = 9/3 = 3

=> Option 1 is correct.

6. As property of vertical line:  75 = x - 10 + 20

=> x = 75 + 10 - 20 = 65 deg

As property of complement angles: 75 + y = 180

=> y = 180 - 75 = 105 deg

=> Option 2 is correct.

7. Yes, the two triangles are congruent (Side-Angle-Side case) with two sides are equal and the pair of angles created by those pair of 2 sides are also equal.

Hope this helps!

:)

4 0
3 years ago
Donna borrowed $10, 500 at a simple interest rate of 4% for 3 years to buy her new car. How much interest would Donna pay and ho
k0ka [10]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

Donna borrowed $10,500 at a simple interest rate of 4% for 3 years to buy her new car. How much interest would Donna pay and how much is the car altogether ?

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

\bullet Principal (P) = $10,500

\bullet Rate of interest (r) = 4%

\bullet Time (t) = 3 years

<h3>To Find:-</h3>

Interest of Donna and amount of car altogether.

<h2>Solution:-</h2>

We know,

{ \boxed{\rm \red {I \: = \frac{Prt}{100}}}}

\therefore I = \frac{10,500 \: × \: 4 \: × \: 3}{100}

I = \frac{126,000}{100}

I = $1260

Now,

Amount of the car = $ (10,500 + 1260)

= $ 11,760

<h3><u>$</u><u>1</u><u>2</u><u>6</u><u>0</u> interest would Donna pay and <u>$</u><u>1</u><u>1</u><u>,</u><u>7</u><u>6</u><u>0</u> is the car altogether. [Answer]</h3>
7 0
3 years ago
Read 2 more answers
Which number is irrational?<br><br><br> 6√<br><br> 1/3<br><br> 0.14............<br><br> 4√
deff fn [24]
Umm, I think it is the first one.
3 0
3 years ago
Read 2 more answers
What is the best estimate for the percent of students scoring greater than 92 on at test?
son4ous [18]

Answer:

80

Step-by-step explanation:

7 0
3 years ago
Check that 2b+b and 3b have the same value when b is 1,2, and 3. Do 2b+b and 3b have the same value for all values of b? Explain
Inessa [10]

Answer:

Expression 2b+b and 3b have same values for all values of b.

Step-by-step explanation:

Given the two expression 2b+b and 3b and values of b as 1, 2 and 3.

Consider first expression that is, 2b+b.

Substituting the value of b=1,

2\left(1\right)+\left(1\right)=2+1=3 ....1

Substituting the value of b=2,

2\left(2\right)+\left(2\right)=4+2=6 ....2

Substituting the value of b=3,

2\left(3\right)+\left(3\right)=6+3=9 ....3

Consider second expression that is, 3b.

Substituting the value of b=1,

3\left(1\right)=3 ....4

Substituting the value of b=2,

3\left(2\right)=6 ....5

Substituting the value of b=3,

3\left(3\right)=9 ....6

For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.

Therefore both expression are same for all values of b.

3 0
3 years ago
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