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Nesterboy [21]
3 years ago
13

HELP PLEASE!!! IM DOING A QUIZ!

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

equivalent = 30w 30(w) 30*w

the rest are non equivalent

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Perform the operation.<br> (4x^2 + 6x + 7) - (-8x^2 – 2x + 6)
LenaWriter [7]

12 {x}^{2}  + 8x + 1

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

(4 {x}^{2}  + 6x + 7) - ( - 8 {x}^{2}  - 2x + 6) \\  = 4 {x}^{2}  + 6x + 7 + 8 {x}^{2}  + 2x - 6 \\  = 4 {x}^{2}  + 8 {x}^{2}  + 6x + 2x + 7 - 6 \\  = 12 {x}^{2}  + 8x + 1

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

8 0
3 years ago
Divide (2x^3-2x-1)/(x-2)
AURORKA [14]
No se;-; think of PEMDAS (parenthesis,exponents,multiplication,division,adding,subtract)
7 0
3 years ago
Use the elimination method to solve this system.
leva [86]

Answer:

The solution for this system is: x = -1, y = 1

Step-by-step explanation:

The problem states that we have to solve this system by the elimination method

In the elimination method, we transform the system in such a way that one variable can cancel each other. With this, we find the result of the other variable. Then, we can replace the variable we found in any of the equations, and we have the value of the variable that we had initially canceled.

In this problem, we have the following system:

1) -6x + 5y = 1

2) 6x + 4y = -10

If we add equations 1) and 2), the variable x is going to be eliminated

1) + 2)

-6x + 6x + 5y + 4y = 1 - 10

9y = -9

y = \frac{-9}{9}

y = -1

Now, we can replace the value of y in any of the equations, to find x:

I will replace in equation 2)

6x + 4y = -10

6x + 4(-1) = -10

6x = -6

x = \frac{-6}{6}

x = -1

The solution for this system is: x = -1, y = 1

5 0
3 years ago
Someone help me quickly plzzz
Black_prince [1.1K]

Answer:

what is the question I don't see it

4 0
3 years ago
Read 2 more answers
Can somebody help me with this problem ?
Tems11 [23]

Step-by-step explanation:

I can't see the question your talking about

5 0
3 years ago
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