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Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
Answer:
import datetime
user = input("Enter date in yyyy,m,d: ").split(",")
int_date = tuple([int(x) for x in user])
year, month, day =int_date
mydate = datetime.datetime(year, month, day)
print(mydate)
x = mydate.strftime("%B %d, %Y was a %A")
print(x)
Explanation:
The datetime python module is used to create date and time objects which makes it easy working with date-time values. The user input is converted to a tuple of integer items, then they are converted to date time objects and parsed to string with the strftime method.
