**Formula
If u want to calculate voltage:
Current x Resistance
so the answer is D
Current:
Voltage ÷ Resistance
Resistance:
Voltage ÷ Current
<u>
Allows you to see two parts of the same worksheet side by side</u>
<u>Option: B</u>
<u>Explanation:</u>
The View Side by Side command helps to see the two documents side by side in Word. When using this feature, both the documents open at the same time in different windows side by side.
To view this, click the View tab in Word and then click the View side by side button. Now the document opens in two windows with side by side views. This is used to compare the documents. In case, if we want to disable this view, click the 'View Side by Side' button again so that it comes to the normal view.
<h2>Answer:</h2>
The correct options are
- Bare metal and hosted
- Memory and operating system based Virtual and physicality
<h2>Explanation:</h2>
There are two types of hypervisors:
Type 1 hypervisor are those hypervisors that run directly on the system hardware such as a “bare metal” embedded hypervisor,
Similarly
Type 2 hypervisor is the kind of hypervisors that runs on a host operating system that provides virtualization services, such as I/O device support and memory management.
The question is not influenced by the fact that it's about intelligence - standard deviation is a way of describing data and it's the same for all kinds of data.
So in general, one standard deviation away from the mean in both directions encompases around 66% of the cases - so here it would be 66% of children.
Additionally, 95% of all children should lie withing two standard deviations - so two standard deviations below or above the average.
Answer:
The final case in selection sort is trivially sorted.
The final iteration in insertion sort is not needed.
Explanation:
For selection sort, you make sub arrays and find the smallest element placing it in the front and repeat until sorted. This guarantees the final element will already be the greatest element, thus it is trivially sorted.
For Insertion sort, you use the initial element and compare it to the previous element and swap if the current is larger than the previous. Using this sort, you will always perform n-1 comparisons where n is the total amount of elements in the array. Thus, there are only 11 iterations for a 12 element array.
Cheers.
