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4 years ago

The graph shows the high temperatures on july 4th over a 15 year period plz look at graph will give brainliest

Mathematics

2 answers:

Artemon [7]4 years ago

8 0

Answer:

Answer: 0.53

Step-by-step explanation:

8 out of the 15 years were in the 90s. So 8/15 is 0.52

jeka57 [31]4 years ago

7 0

Well there are 8 years that show over 90°. Using those statistics you can show that as 8/15 for a probability.

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Describe and correct the error below.

statuscvo [17]

Step-by-step explanation:

It is given that,

-2.2 × 3.7 = 8.14

The first number is -2.2

The second number is 3.7

We know that, (-) × (+) = - (the answer is a negative)

If we multiply -2.2 and 3.7, we will get -8.14.

But in the given case, the answer is 8.18 instead of -8.14. Hence, this is the only error.

8 0

3 years ago

PLEASE HELP ILL GIVE BRAINILEST ANSWER!

skelet666 [1.2K]

Answer:

Angle A=73

Step-by-step explanation:

5 0

3 years ago

I don’t understand how to do this

Simora [160]

It's looking for the measures

m<F + m<G = 180°

(4x)° + (8x)° = 180°

12x = 180°
÷12 ÷12

x = 15

check your work

m<F + m<G = 180°

(4x)° + (8x)° = 180°

4(15)° + 8(15)° = 180°

60° + 120° = 180°

3 0

4 years ago

-3x + 3y = 4 -x+ y = 3

Natalka [10]

Answer:

No solution

Step-by-step explanation:

-3x + 3y = 4

-x + y = 3

Solve the equation for x:

Move the variable to the right side and change its sign

-x + y = 3

-x = 3 - y

Change the signs on both sides of the equation

-x = 3 - y

x = -3 + y

Substitute the given value of x into the equation -3x + 3y = 4

-3x + 3y = 4

x = -3 + y

-3(-3+y)+3y=4

Solve the equation for y

-3(-3+y)+3y=4

y = 0

There is no solution for y.

And since there's no solution for y, the system has no solution.

6 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago