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3 years ago

What is the period of the function F(x) = -4sec (1/2 x)

Mathematics

1 answer:

serg [7]3 years ago

8 0

Answer:

A) 4π

Step-by-step explanation:

The period of a secant function, f(x)=a*sec(bx+c)+d, is defined as 2π/|b| where b is the distance of the period. Since we know b=1/2 given by the function, then the period is 2π/|1/2|=2π/(1/2)=2π(2/1)=4π.

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After 3 minutes, a submarine had descended to −320 feet. After 8 minutes, the submarine had descended to −420 feet. Assuming a l

Alenkasestr [34]

Answer:

d(t) = -20t -260

Step-by-step explanation:

We are given two points ...

(t, d) = (3, -320) and (8, -420)

The 2-point form of the equation of a line can be useful when 2 points are given.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

Substituting the given points, we have ...

d(t) = (-420 -(-320))/(8 -3)(t -3) -320

d(t) = -20(t -3) -320

d(t) = -20t -260

5 0

3 years ago

PLEASE HELP ME I NEED THE ANSWER ASAP THANK YOU SO MUCH!!

Ostrovityanka [42]

dark blue is the answer

6 0

3 years ago

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A curve along a highway is to be designed for cars moving at 100 kilometers per hour. Find the angle of banking if the radius of

statuscvo [17]

Answer:

hope this will help you

Step-by-step explanation:

.........

5 0

3 years ago

Brainliest question please help please help me now plz

Kruka [31]

Answer:

Option A) Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

$d\sqrt{(y2-y1)^2+(x2-x1)^2 }$

we have

A(-5,-8),M(-1,-3)

substitute the values

$r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}$

$r=\sqrt{(5)^{2}+(4)^{2}}$

$r=\sqrt{41}\ units$

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

$d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}$

$d=\sqrt{(2)^{2}+(-6)^{2}}$

$d=\sqrt{40}\ units$

$\sqrt{40}\ units< \sqrt{41}\ units$

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

Hope that helped :)

8 0

3 years ago

If CD=18, find the value of EB.

aliina [53]

Step-by-step explanation:

Chord AB and Chord CD are equidistant from the center of the circle.

$\therefore \: chord \: AB \cong chord \: CD \\ \\ \therefore \: \frac{1}{2} \: \: AB \cong \frac{1}{2} \: \: CD \\ \\ \therefore \: EB = \frac{1}{2} \: \times 18\\ \\ \huge \purple{ \boxed{\therefore \: EB =9}}$

5 0

3 years ago