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Mamont248 [21]
3 years ago
14

Graph r < – 4 orr > 3?

Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

Graph r < – 4 orr > 3?

Step-by-step explanation:

Graph r < – 4 orr > 3?

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Divide 7 by 8 then multiply what you get by 100.
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Determine the correct scientific notation form of the number. 327,000,000,000
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B. 3.27 x 10^11.

Step-by-step explanation:

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3.27 x 10^11.

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A store is having a sale on liquid soap and sponges. The cost of 6 bottles of soap is $9.12. The cost of 4 sponges is $5.00 what
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$6.79

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3 years ago
PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS
Elina [12.6K]

You want to end up with A\sin(\omega t+\phi). Expand this using the angle sum identity for sine:

A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi

We want this to line up with 2\sin(4\pi t)+5\cos(4\pi t). Right away, we know \omega=4\pi.

We also need to have

\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}

Recall that \sin^2x+\cos^2x=1 for all x; this means

(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}

Then

\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)

So we end up with

2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)

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2 years ago
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