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4 years ago

What do you say when you meet a two headed dragon

Mathematics

2 answers:

Stolb23 [73]4 years ago

6 0

Hello hello is the answer please give me brainliest

Damm [24]4 years ago

5 0

Https://www.youtube.com/watch?v=yrYYDyuuKHE

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Please help I really need it will give brainliest answer

Lisa [10]

Answer:

$12b^{6}$ + 6b³ - 18b²

Step-by-step explanation:

6 0

3 years ago

How do you write 47/50 as a percentage?

enot [183]

Answer:

94%

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Write logarithmic expression as a single logarithm.<br><br> (1/3) log 8 + log 6 - log 4

marusya05 [52]

Answer:

log3

Step-by-step explanation:

$\frac{1}{3} log8 + log6 - log4 \\ = log {8}^{ \frac{1}{3} } + log( \frac{6}{4} ) \\ = log2 + log( \frac{3}{2} ) \\ = log(2 \times \frac{3}{2} ) \\ = log3$

7 0

4 years ago

one gym membership charges $10 a month with a sign-up fee of $45. Another gym does not charge patrons a sign-up fee but costs $2

ss7ja [257]

After 3 months memberships will cost the same.

We have,

Cost of Membership of 1st gym = $ 10 per month

And, the Cost of the sign-up fee for 1st gym = $ 45

And,

Cost of Membership of 2nd gym = $ 25 per month

And, the Cost of the sign-up fee of the 2nd gym = $ 0

Now,

Let the number of months = m

So,

According to the question;

45 + 10m = 25m

⇒

25m - 10m = 45

15m = 45

m=3

So, After 3 months memberships will cost the same.

Learn more about memberships here:

brainly.com/question/352169

#SPJ10

4 0

2 years ago

A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar

Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = $\sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }$

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = $\sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }$

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0

3 years ago