AC = 2 BD
Distance BD = √[(2.5+1)^2 +(3-3)^2]
Distance BD = √(3.5)^2
Distance BD = 3.5
AC = 2 * 3.5 = 7
Answer
d. 7
Use A Graph
I Hope This Helped!
Answer:
see below and attached
Step-by-step explanation:
To solve a system of quadratic equations:
- Equal the equations then rearrange so that it is set to zero.
- Use the quadratic formula to solve.
I have done this (see attached workings) but cannot get any of the solutions you've provided. I have even graphed the two functions, and the points of intersection concur with my workings (see attached graph).
The heck, what math are you in?
Let x = hours to meet
train one has a 2 hour head start or 210 km head start
210 + 105x = 135x
30x = 210
x = 7 hours to meet