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viva [34]
3 years ago
12

Plant and animal cells differ in shape. Plant cells are usually box-shaped, while animal cells tend to be irregularly shaped. Wh

ich of the following comparisons correctly identifies the reason for this difference?
Unlike plant cells, animal cells contain lysosomes.
Unlike plant cells, animal cells have mitochondria.
Unlike plant cells, animal cells lack a cell wall.
Unlike plant cells, animal cells lack chloroplasts.
Biology
2 answers:
Alchen [17]3 years ago
5 0

Unlike plant cells, animal cells lack a cell wall.


Scilla [17]3 years ago
3 0
The best and most correct answer among the choices provided by your question is the third choice or letter C.

Plant cells are usually box-shaped, while animal cells tend to be irregularly shaped because u<span>nlike plant cells, animal cells lack a cell wall. </span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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3 years ago
The CRISPR/Cas9 system can cleave genomic DNA at sequences other than the desired target, a phenomenon referred to as off target
Deffense [45]

Answer:

The minimum length of a sgRNA sequence to avoid off target cleavage by the CRISPR/Cas system in the fly fruit genome is 14 bases

Explanation:

We are trying to use the CRISPR/Cas system to cleavage the genome of the fruit fly (which is 1.4x10^8 bp long). Also we desire the cleavage to be unique. That means we need a target sequence long enough to be able to assume it will only appear once in the genome.

First, we should think that in every position, we can find one out of four different nucleotide (A, C, T, G). So, the probability of getting a sequence of a given length "n" will be (1/4)^n (We are assuming that the probability of finding a nucleotide in the position "i", it's independent of the nucleotide we find in any other position "j").

Also, to know how many times a sequence will appear in a genome (the expected value of occurrence), we must multiply the probability of that sequence to randomly occur by the length of the genome. For our specific example, the number of occurence of a sequence of length "n" is:

nºoccurence=[(1/4)^n]*1.4*10^8

But in this case, what we want is the expected number of times the sequence will appear to be 1, and we want to obtain the length of the target sequence (n).

Given the information above, we know that:

[(1/4)^n]*1.4*10^8 =1

[(1/4)^n]=(1/1.4*10^8)=1.4*10^-8

Then, if we want to calculate n, we can use logarithms and its properties to get:

log[(1/4)^n]=log[1.4*10^-8]

n*log[(1/4)]=log[1.4*10^-8]

n=log[1.4*10^-8]/log[(1/4)] => n=13.29 approximately.

As the sequence needs to have a natural number of elements, <u>we can conclude that using a target sequence of a minimum of 14 bases with the CRISPR/Cas system in the fly fruit genome should be enough to avoid off target cleavage.</u>

3 0
3 years ago
What is the nervous system composed of?
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Answer: D) the central and peripheral nervous systems

hope this helps

8 0
2 years ago
If decomposers were added to an energy pyramid that contains producers, primary consumers, and secondary consumers, which trophi
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Which of the following is not a source of atmospheric carbon?
garik1379 [7]

Answer:

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5 0
3 years ago
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