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Anton [14]
3 years ago
14

ming took a cab across town . his fare was $22 and he leaves an 18% tip . what is the total amount ming pays the cab driver ?

Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

$25.96

Step-by-step explanation:


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For question 2 not 3 :)
BabaBlast [244]

Answer:

2.5

Step-by-step explanation:

6 0
4 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
4 years ago
A proportional relationship is shown in the table below: what is the slope and what numbers do i graph. ty besties
dangina [55]

Answer:

The slope of the line is m = \frac{3}{5} and the equation of the line is y = \frac{3}{5}\cdot x.

Step-by-step explanation:

From table we understand that slope of the line is constant, that is, for each change of x there is one and only change in y, fulfilling the main characteristic of a line and we can determine the slope for every point of the line by means of the following expression:

m = \frac{y_{f}-y_{o}}{x_{f}-x_{o}} (1)

Where:

x_{o}, x_{f} - Initial and final x-coordinates of the line.

y_{o}, y_{f} - Initial and final y-coordinates of the line.

If we know that (x_{o}, y_{o}) = (0,0) and (x_{f},y_{f}) = (8,4.8), then the slope of the line is:

m = \frac{4.8-0}{8-0}

m = \frac{3}{5}

From graph we conclude that x-intercept of the line is b = 0. Hence, the equation of the line is y = \frac{3}{5}\cdot x and we proceed to plot the expression with the help of a graphing tool.

5 0
3 years ago
A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading
Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

b.

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0
4 years ago
Please answer right away and don’t guess
ivolga24 [154]

im pretty sure the answer is 30

5 0
3 years ago
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