4 - -2
,...........................
Consider the function

, which has derivative

.
The linear approximation of

for some value

within a neighborhood of

is given by

Let

. Then

can be estimated to be

![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since

for

, it follows that

must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function

. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
Answer:
x=1
Step-by-step explanation:
3^x +1
f(x)=3x+1
f(x) =g(x)
3x +1 =3^x +1
Subtract 1 from each side
3x = 3^x
Let x =1
3*1 = 3^1
3=3
<u>X - Intercept</u>
f(x) = -x² + 4x - 4
0 = -x² + 4x - 4
x = <u>-(4) +/- √((4)² - 4(-1)(-4))</u>
2(-1)
x = <u>-4 +/- √(16 - 16)</u>
-2
x = <u>-4 +/- √(0)
</u> -2<u>
</u> x = <u>-4 +/- 0
</u> -2<u>
</u> x = <u>-4 + 0</u> x = <u>-4 - 0</u>
-2 -2
x = <u>-4</u> x = <u>-4</u>
-2 -2
x = 2 x = 2
The solution to the problem is {2, 2}, or {2}. The x - intercept of the problem is (2, 0).
<u>Y - Intercept</u>
f(x) = -x² + 4x - 4
f(x) = -(0)² + 4(0) - 4
f(x) = -(0) + 0 - 4
f(x) = -0 + 0 - 4
f(x) = 0 - 4
f(x) = -4
The y - intercept of the problem is (0, -4).
<u />
The density of the gold sample is 19.3g/cm³
Let the mass of the gold sample be represented by m
m = 579 g
Let the volume of the gold sample be represented by V
V = 30 cm³
Let the density of the gold sample be represented by ρ
The formula for the density is:


The density of the gold sample is 19.3g/cm³
Learn more here: brainly.com/question/17780219