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3 years ago

Which is not a statistical question that might be used to gather data

1 answer:

3 0

C because you can’t get multiple answers, the rest of the answers will give you multiple answers ,therefore ,see will be it

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What’s the answer to 2x2

Umnica [9.8K]

the answer to 2x2 is 4 so 2 x 2= 4

6 0

3 years ago

Read 2 more answers

The population of a suburb grows at a rate proportional to the population. Suppose the population doubles in size from 3000 to 6

frozen [14]

Answer:

$P(t) = 3000e^{0.1155t}$

Step-by-step explanation:

The growth of the population can be modeled by the following differential equation:

$\frac{dP}{dt} = rP$

Where r is the growth rate, P is the population, and t is the time measures in months.

I am going to solve the above differential equation with the separation of variables method.

$\frac{dP}{P} = rdt$

Integrating both sides:

$ln P = rt + P(0)$

Where P(0) is the initial condition

We need to isolate P in this equation, so we do this

$e^{ln P} = e^{rt + P(0)}$

$P(t) = P(0)e^{rt}$

The problem states that P(0)=3000, so:

$P(t) = 3000e^{rt}$

The problem wants us to find the value of r:

It states that the population doubles in size from 3000 to 6000 in a 6- month period, meaning that P(6) = 6000. So

$6000 = 3000e^{6r}$

$e^{6r} = 2$

To isolate 6r, we apply ln to both sides.

$ln (e^{6r}) = ln 2$

$6r = 0.693$

$r = \frac{0.693}{6}$

r = 0.1155

The particular solution to the differential equation with the initial condition P(0)=3000 is:

$P(t) = 3000e^{0.1155t}$

5 0

3 years ago

Which statement is true

xenn [34]

$\dfrac{3}{4} = \dfrac{3 \times 3}{4 \times 3} = \dfrac{9}{12}$

$\dfrac{4}{6} = \dfrac{4 \times 2}{6 \times 2} = \dfrac{8}{12}$

$\dfrac{9}{12} \ \textgreater \ \dfrac{8}{12}$

$\dfrac{3}{4} \ \textgreater \ \dfrac{4}{6}$

7 0

2 years ago

Which ratio correctly compares 30 in. to 2 ft, when the lengths are written using the same units?

saul85 [17]

<span> D. 15:1 is equivalent to 30:2. (:</span>

6 0

2 years ago

Solve 2x + 5y = 20; 3x - 10y = 37 by elimination. How do you do this? Thank-you!

mr Goodwill [35]

$\left\{\begin{array}{ccc}2x+5y=20&\text{multiply both sides by 2}\\3x-10y=37\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}4x+10y=40\\3x-10y=37\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad7x=77\qquad\text{divide both sides by 7}\\.\qquad\boxed{x=11}\\\\\text{Put the value of x to the first equation:}\\\\2(11)+5y=20\\\\22+5y=20\qquad\text{subtract 22 from both sides}\\\\5y=-2\qquad\text{divide both sides by 5}\\\\\boxed{y=-\dfrac{2}{5}}\\\\Answer:\ \boxed{x=11\ and\ y=-\dfrac{2}{5}}$

6 0

2 years ago