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3 years ago

14

Factor the expression using GCF

1 answer:

julsineya [31]3 years ago

6 0

7 + 14
7(1 + 2)

44 - 11
11( 4 - 1)

18 - 12
6(3 - 2)

70 + 95
5(14 + 19)

60 - 36
12(5 - 3)

100 - 80
20(5 - 4)

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Sherri has 23 pieces of jewelry to sell. She sells the bracelets for $2 and the necklaces for $3, and earns a total of $55. If t

Nutka1998 [239]

X + y = 23
2x + 3y = 55

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3 years ago

Read 2 more answers

The figures shown are similar. What is the scale factor? A.1/9 B.4/7 C.6/7 D.3/7

Rom4ik [11]

<span>B.4/7

You can check by taking 21 * 4/7 = 12 which is figure 2
</span>

6 0

3 years ago

How many one-to-one correspondences are there between two sets with 5 elements each?

Fittoniya [83]

1st element can be matched with 5
2nd element can be matched with 4
3rd element can be matched with 3
etc.
Total number of correspondences = 5*4*3*2*1 = 120

7 0

3 years ago

Find the area of the shaded region

Dimas [21]

The area of the shaded region is 15.453 square units.

Step-by-step explanation:

Step 1:

The given shape consists of a rectangle and two circles.

The length of the rectangle is given as 12 cm. Both the diameters of the circles equal 12 cm. So each circle has a diameter of 6 cm and thus a radius of 3 cm.

The diameter of the circle is equal to the width of the rectangle.

So the rectangle has a length of 12 cm and a width of 6 cm. The circles have radii of 3 cm each.

Step 2:

The area of the rectangle $= (l)(w) = (12)(6) = 72$ square cm.

The area of each circle $= \pi r^{2} = (3.1415)(3^{2} ) = 28.2735$ square cm.

The area of both circles $=2(28.2735) = 56.547$ square cm.

The area of the shaded region is the difference between the area of the rectangle and the area of both circles.

The area of the shaded region $= 72 - 56.547 = 15.453$ square units.

The area of the shaded region is 15.453 square units.

6 0

3 years ago

If a computer network has 60 switching nodes, in how many ways can 2 or 3 nodes fail?___________

notka56 [123]

Answer:

There are 35990 ways in which 2 or 3 nodes fail

Step-by-step explanation:

Given : A computer network has 60 switching nodes.

To Find : In how many ways can 2 or 3 nodes fail?

Solution:

We are supposed to find no. of ways can 2 or 3 nodes fail.

So, we will use combination here .

No. of ways can 2 or 3 nodes fail= $^{60}{C_2 +^{60}C_3$

Formula : $^nC_r =\frac{n!}{r!(n-r)!}$

No. of ways can 2 or 3 nodes fail= $\frac{60!}{2!(60-2)!}+\frac{60!}{3!(60-3)!}$

= $35990$

Hence there are 35990 ways in which 2 or 3 nodes fail

5 0

3 years ago