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3 years ago

8

a cyclist rode the first 32 mile portion of his workout at a constant speed. For the 28 mile cooldown portion of his workout, he

reduces his speed by 2 miles per hour. Each portion of the workout took the same time. Find the cyclists speed during the first portion and find his speed during the cooldown portion.

1 answer:

Lapatulllka [165]3 years ago

8 0

The first portion is 2 and his speed during the cool down portion also 2 so I think it should be 2+2 which is 4

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What expression shows 4 less than a number?<br> A. n + 4<br> B. n - 4<br> C. 4 - n<br> D. n(4)

Elis [28]

Answer:

B

Step-by-step explanation:

Because the expression in b is saying whatever number n is say 9 then your subtracting 4 by N or like I said take 9 for an example which=5

hope it helps

3 0

2 years ago

Read 2 more answers

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Help needed! How do I solve this?<br>Excuse the answers that are already in there!

anastassius [24]

1) 108
2) 72
3) 36
4) 72
5) 72
6) 144
7) 72
8) 72
9) 108
10) 108
I hope this helped

8 0

3 years ago

WILL GIVE U BRAIN IF UR SMART ENOUGH TO ANSWER AND FREE 75 PTS

atroni [7]

Answer:

x = 96

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

olchik [2.2K]

To solve this we are going to use the future value of annuity ordinary formula: $FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]$
where
$FV$ is the future value
$P$ is the periodic payment
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year
$k$ is the number of payments per year
$t$ is the number of years

We know for our problem that $P=6200$ and $t=5$ . To convert the interest rate to decimal form, we are going to divide the rate by 100%:
$r= \frac{6}{100} =0.06$
Since the deposit is made semiannually, it is made 2 times per year, so $k=2$ .
Since the type of the annuity is ordinary, payments are made at the end of each period, and we know that we have 2 periods, so $n=2$ .
Lets replace the values in our formula:

$FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]$
$FV=6200[ \frac{(1+ \frac{0.06}{2} )^{(2)(5)} -1}{ \frac{0.06}{2} } ]$
$FV=71076.06$

We can conclude that the correct answer is <span>$71,076.06</span>

8 0

3 years ago