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2 years ago

Fish decrese 25% each year. If there are 60 fish in the lake last year, how many will there be this year?

Mathematics

1 answer:

PolarNik [594]2 years ago

7 0

Answer:

Step-by-step explanation:

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Macy is tutoring students in mathematics during her summer break. She charges $20 for a 30 minute session and $35 for an hour. T

Zanzabum

If she only had 1 hour sessions she had 8 sessions in the first week because if you do 35 times 8 you get 280.

7 0

3 years ago

What would the value of x be

nlexa [21]

Answer:

65°

Step-by-step explanation:

The sum of the interior angles of a quadrilateral is 360 degrees.

65+115+115=295

360-295=65

Answer: 65°

8 0

3 years ago

Read 2 more answers

Can someone please answer. There is a picture. There is only one question. Thank you so much

fomenos

4 0

3 years ago

Help anyone can help me do the question,I will mark brainlest.

Marrrta [24]

Part (a)

The radius is r = 42 because OA = 42.

The circumference, aka distance around the circle, is

C = 2*pi*r

C = 2*(22/7)*42

C = 264

We're told that arc AB is 110 mm which is 110/264 = 5/12 of the full distance around the circle.

So we'll apply 5/12 to the full rotation 360 to get (5/12)*360 = 150

<h3>Answer: 150 degrees</h3>

==============================================================

Part (b)

Compute the area of the full circle

A = pi*r^2

A = (22/7)*(42)^2

A = 5544

Then take 5/12 of this because we only want 5/12 of the full circle area (to get the area of the shaded pizza slice)

(5/12)*(5544) = 2310

<h3>Answer: 2310 square mm</h3>

==============================================================

Side note: Both answers are approximate because pi = 22/7 is approximate.

5 0

2 years ago

Formulate the following problem as least squares problems. For each problem, give a matrixA and a vector b such that the problem

hammer [34]

Answer:

a) $A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]$

$b=\left[\begin{array}{ccc}0\\1\end{array}\right]$

b) $||Ax-b||^{2} =(-bx_{2}+4)^{2} (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}$

c) $A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]$

$x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]$

Step-by-step explanation:

a) considering the equation:

Minimize $x_{1}^{2} +2x_{2}x^{2} +3x_{3}^{2}+(x_{1} -x_{2} +x_{3} -1)^{2} +(-x_{1} -4x_{2} +2)^{2}$

$A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]$ (matrix A)

vector b

$b=\left[\begin{array}{ccc}0\\1\end{array}\right]$

b) If Pxn is matrix B and p-vector d, we have:

minimize $(-6x_{2}+4)^{2} +(-4x_{1} +3x_{2} -1)+(x_{1} +8x_{2} -3)^{2}$

$Ax=\left[\begin{array}{ccc}0&-6&0\\-4&3&0\\1&8&0\end{array}\right]$

$\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-4\\1\\3\end{array}\right]$

$Ax-b=\left[\begin{array}{ccc}-bx_{2}+4 \\-4x_{1}+3x_{2}-1 \\x_{1}+8x_{2}-3 \end{array}\right] =1$

$||Ax-b||^{2} =(-bx_{2}+4)^{2} (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}$

c) minimize $2(-bx_{2}+4)^{2} +3(-4x_{1} +3x_{2} -1)^{2} +4(x_{1} -x_{2} -3)^{2} -(6\sqrt{2}x_{2} +4\sqrt{2} )^{2} +(-4\sqrt{3} x_{1} +3\sqrt{3}x_{2} -\sqrt{3})^{2} +(2x_{1} -16x_{2} -6)^{2}$

in matrix:

$A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]$

$x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]$

6 0

3 years ago