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USPshnik [31]
3 years ago
9

A rectangular photograph has an area of 13425 in² and a width of 1115 in.

Mathematics
1 answer:
satela [25.4K]3 years ago
4 0
The photograph is said to be rectangular therefore the area of such should be the same as a rectangle which is the product of its length and width. We are given the width and the area of the photograph. We can easily calculate the length by dividing the area by the width which will yield a value of 12.04 in. This is the length.
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If 5/8 is multiplied by 4/5 will the product be greater than the two factors? Explain.
STALIN [3.7K]

Answer:

Step-by-step explanation:

4/5 is less than 1, so multiplying 5/8 by 4/5 results in a product smaller than the two factors.

6 0
3 years ago
Which points are on the perpendicular bisector of the given segment? Check all that apply. Please explain how you got your answe
ser-zykov [4K]
First, you have to find the equation of the perpendicular bisector of this given line. 
to do that, you need the slope of the perpendicular line and one point.
Step 1: find the slope of the given line segment. We have the two end points (10, 15) and (-20, 5), so the slope is m=(15-5)/(10-(-20))=1/3
the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3 
step 2: find the middle point: x=(-20+10)/2=-5, y=(15+5)/2=10      (-5, 10)
so the equation of the perpendicular line in point-slope form is (y-10)=-3(x+5)

now plug in all the given coordinates to the equation to see which pair fits:
(-8, 19): 19-10=9, -3(-8+5)=9, so yes, (-8, 19) is on the perpendicular line. 

try the other pairs, you will find that (1,-8) and (-5, 10) fit the equation too. (-5,10) happens to be the midpoint. 

4 0
3 years ago
Read 2 more answers
NEED HELP ASAP!!! What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15 A stem-and-lea
monitta
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.

Find the median of the data (30.5)

Find the median of the lower half and the median of the upper half.

Subtract these two values.

The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
                            27.5                40.5
40.5-27.5 = 13

The interquartile range is 13.
3 0
3 years ago
Read 2 more answers
Can somebody help me it's on pribability
lbvjy [14]
11-10
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6 0
3 years ago
The graph above shows the cost of a large pizza
madreJ [45]
I would say the first choose that the vertical axis should use $0.50 intervals instead of $1.
Because this would make it much easier to read and understand and would it would also be more accurate.
5 0
3 years ago
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