Answer:

Step-by-step explanation:
We can try and isolate m on one side of the equation by following the rules of simplifying equations.

Hope this helped!
There are 2 options to solve that.
1. The first one is by derivatives.
f(x)=x^2+12x+36
f'(x)=2x+12
then you solve that for f'(x)=0
0=2x+12
x=(-6)
you have x so for (-6) solve the first equation, then you find y
y=(-6)^2+12*(-6)+36=(-72)
so the vertex is (-6, -72)
2. The second option is to solve that by equations:
for x we have:
x=(-b)/2a
for that task we have
b=12
a=1
x=(-12)/2=(-6)
you have x so put x into the main equation
y=(-6)^2+12*(-6)+36=(-72)
and we have the same solution: vertex is (-6, -72)
For next task, I will use the second option:
y=x^2-6x
x=(-b)/2a
for that task we have
b=(-6)
a=1
x=(6)/2=3
you have x so put x into the main equation
y=3^2+(-6)*3=(--9)
and we have the same solution: vertex is (3, -9)
It is a square trinomial:
4v^2 - 16v + 7 = 0
lets multiply and divide all by 4, the square term coefficient:
(16v^2 - 16(4)v + 28)(1/4) = 0
(4v - 14)(4v - 2)<span>(1/4) = 0
</span>factor 1/4
(4v - 14)(4v - 2)(1/2)<span>(1/2)</span> = 0
and divide each:
(2v - 7)(2v - 1) = 0