Answer:
50
Step-by-step explanation:
If the first statement its true (At most 0 of the statements are true), there are not true statements in the paper. So, the first statement its false.
Now, if the first statement its false, this mean there must be at least 1 true statement in the paper.
Now, if the second statement its true ( at most 1 of the statements are true) this implies that the third statement its true (if "at most 1" its true, then "as most 2" must be true).
If any statement (besides the first) its true, then all the statement that follows it must be true.
The first non false statement, then, must be the statement made by the person 51: "At most 50 statements are true"
And the 49 statements that follows are true as well.
The answer is B..........................
Answer:
The quadratic x2 − 5x + 6 factors as (x − 2)(x − 3). Hence the equation x2 − 5x + 6 = 0
has solutions x = 2 and x = 3.
Similarly we can factor the cubic x3 − 6x2 + 11x − 6 as (x − 1)(x − 2)(x − 3), which enables us to show that the solutions of x3 − 6x2 + 11x − 6 = 0 are x = 1, x = 2 or x = 3. In this module we will see how to arrive at this factorisation.
Polynomials in many respects behave like whole numbers or the integers. We can add, subtract and multiply two or more polynomials together to obtain another polynomial. Just as we can divide one whole number by another, producing a quotient and remainder, we can divide one polynomial by another and obtain a quotient and remainder, which are also polynomials.
A quadratic equation of the form ax2 + bx + c has either 0, 1 or 2 solutions, depending on whether the discriminant is negative, zero or positive. The number of solutions of the this equation assisted us in drawing the graph of the quadratic function y = ax2 + bx + c. Similarly, information about the roots of a polynomial equation enables us to give a rough sketch of the corresponding polynomial function.
As well as being intrinsically interesting objects, polynomials have important applications in the real world. One such application to error-correcting codes is discussed in the Appendix to this module.
Answer:
Option (6)
Step-by-step explanation:
By applying sine rule the given triangle XYZ,
sin(X) =
Measure of opposite side (XY) = 12
Measure of Hypotenuse (XZ) = 37
By substituting these values in the given expression,
sin(X) =
Therefore, Option (6) will be the correct option
Answer:
x = 10
Step-by-step explanation:
28/20 = 1.4
4x+2/3x = 1.4
4x+2/3x = 14/10
40x+20 = 42x
40x-42x = -20
-2x = -20
-x = -20/2
-x = -10
x = 10