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Hitman42 [59]
3 years ago
14

What’s 1 +1&:$:&!::’kejdnd

Mathematics
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

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Step-by-step explanation:

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A deep sea diving bell is being lowered at a constant rate. After 10 ​minutes, the bell is at a depth of 600 ft. After 40 minute
Degger [83]
<h2>Average rate of lowering per​ minute = 36.67 ft/min</h2>

Step-by-step explanation:

After 10 ​minutes, the bell is at a depth of 600 ft

After 10 minutes

                   Depth of bell = 600 ft

After 40 minutes the bell is at a depth of 1,700 ft.

After 40 minutes

                   Depth of bell = 1700 ft

Time gap = 40 - 10 = 30 minutes

Depth fallen = 1700 - 600 = 1100 ft

We have

           Depth fallen = Average rate of lowering per​ minute x Time gap

           1100 = Average rate of lowering per​ minute x 30

           Average rate of lowering per​ minute = 36.67 ft/min

7 0
3 years ago
katie bought 12 roses she gave some a way and now has 4 roses left.how many roses did katie give away
Firlakuza [10]
Rosie gave away 8 roses
8 0
3 years ago
Read 2 more answers
Leonard made the 3-d shape below for an art project. He wants to paint it blue.
GalinKa [24]

Answer:

Is 10cm and 6 cm an option

4 0
2 years ago
PLASE ANSWER THIS QUESTION ​I GIVE YOU 18 POINTS
sukhopar [10]

Answer:

(a) 144

(b) 117

(c) 360

(d) 588

(e) 5472

Step-by-step explanation:

To find the LCM of two numbers, first find the prime factorization of each number. Then the LCM is the product of common and not common factors with the larger exponent.

2.

(a)

72 = 2^3 \times 3^2

144 = 2^4 \times 3^2

LCM = 2^4 \times 3^2 = 8 \times 9 = 144

(b)

39 = 3 \times 13

117 = 3^2 \times 13

LCM = 3^2 \times 13 = 117

(c)

72 = 2^3 \times 3^2

90 = 2 \times 3^2 \times 5

LCM = 2^3 \times 3^2 \times 5 = 360

(d)

84 = 2^2 \times 3 \times 7

147 = 3 \times 7^2

LCM = 2^2 \times 3 \times 7^2 = 588

(e)

152 = 2^3 \times 19

288 = 2^5 \times 3^2

LCM = 2^5 \times 3^2 \times 19 = 5472

6 0
3 years ago
The students in Ms. Dodd's class recorded the height in feet of palm trees on school property. Their heights were as follows:
dlinn [17]

Answer:

B

Step-by-step explanation:

8 0
2 years ago
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