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miv72 [106K]
3 years ago
13

I need to rotate this 180 degrees about the origin and list the new coordinates.

Mathematics
1 answer:
Bess [88]3 years ago
8 0
Your answer is going to be positive 1 to positive 3

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There are 2 pecks in one kenning there are 2 kennings in 1 bushel there are 8 bushels in1 quarter there are 5 quarters in 1 load
Delicious77 [7]

Answer:

yes 1 2 3

Step-by-step explanation:

7 0
3 years ago
I need help with # 14 and 15 ASAP... It is due tomorrow ..can some one please help me with it
Angelina_Jolie [31]

Answer:

See explanation

Step-by-step explanation:

A. Gasoline fill-up fee = $4.50

Cost per hour = $40

Average cost = C

Number of hours the scootcar is rented = h

Cost per h hours = $40h

Total cost = $40h + $4.50

Hence,

C = 40h+4.5

B. To plot the graph of the function, find h- and C- intercepts.

When h = 0, then C = 4.5, and we have point (0,4.5)

When C = 0, then 0 = 40h + 4.5, h = -45/400 = -0.1125, and we have point (-0.1125,0)

Plot these two points and connect them with a straight line.

Graph is attached, but you should take only that part of the graph that corresponds to points with h > 0, because the number of hours cannot be negative

8 0
3 years ago
80% of what number is 24
pochemuha
24* 80/100 = 24*8/10 = 19.2 is the answer.
6 0
3 years ago
Read 2 more answers
What is the value of x in the solution to the system<br> x+y=10<br> x-y=4
ANEK [815]

Answer:

x = 7; y = 3

Step-by-step explanation:

I used the Trial and Error Method and found that x = 7 and y = 3

=> 7 + 3 = 10

=> 10 = 10. ✔

=> 7 - 3 = 4

=> 4 = 4. ✔

Therefore, x = 7 and y = 3

Hoped this helped.

6 0
2 years ago
2. Margie Spencer wants to have $100,000 in her savings account in 20 years. If her account pays 6.6% annual
WITCHER [35]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$100000\\ P=\textit{original amount deposited}\\ r=rate\to 6.6\%\to \frac{6.6}{100}\dotfill &0.066\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &20 \end{cases}

100000=P\left(1+\frac{0.066}{2}\right)^{2\cdot 20}\implies 100000=P(1.033)^{40} \\\\\\ \cfrac{100000}{1.033^{40}}=P\implies 27288.97\approx P

7 0
2 years ago
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