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tatiyna
3 years ago
6

Use De Moivre’s Theorem to compute the following:

ula1" title="[3(cos27+isin27)}^5" alt="[3(cos27+isin27)}^5" align="absmiddle" class="latex-formula"> Please explain step by step how it works!
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0
Hello: 
<span>Use De Moivre’s Theorem : 
</span>(3(cos27 +isin27)^5 = 3^5( cos(27 × 5) +isin(27 × 5))
                                = 3^5 ( cos(135)+i sin(135))
                                = 3^5(-√2/2+i √2/2) 
because :  cos(135) = -√2/2    and   sin(135) = √2/2
(3(cos27 +isin27)^5 = (- 3^5√2/2)+ i ( 3^5√2/2)  ...(form : a+ib  when
a= (- 3^5√2/2)  and  b = ( 3^5√2/2)
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Answer:

5

Step-by-step explanation:

The nth term of the geometric sequence is

a_n=(-2)(5)^{n-1}

In general the nth term of a geometric sequence is

a_n=a_1(r)^{n-1}

By comparism;

r=5 is the common ratio of the sequence.

Or

a_1=(-2)(5)^{1-1}=-2

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3 years ago
6n &lt; -12 pls show work​
dalvyx [7]

Answer:

Step-by-step explanation:

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3 years ago
The high school graduating class of 2010 was 260 people. Five years later the high school graduating class was 320 people. By ap
jeka94

Answer:

The high school graduating class changed by approximately 23%

Step-by-step explanation:

we have

The high school graduating class of 2010 was 260 people

Five years later the high school graduating class was 320 people.

we know that

260 people represent the 100%

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The difference is (320-260)=60 people

using proportion

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3 years ago
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crimeas [40]

Answer:

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I hope this helps have a good day

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3 years ago
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