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VashaNatasha [74]

3 years ago

8

A segment is divided into two parts having lengths in the ratio of 5:3. If the difference between the length of the parts is 6",

find the length of the longest part

2 answers:

aleksley [76]3 years ago

7 0

Answer: the correct answer is 15 I believe.

masha68 [24]3 years ago

5 0

A) x / y = 3 / 5
A) 5x = 3y
A) 5x - 3y = 0
B) y - x = 6
B) 3y -3x = 18
Adding A) and B)
2x = 18
x = 9
y = 15

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Which describes how to calculate the range of this data set?

ELEN [110]

Answer:

B) Subtract 12-4 to calculate the range of this data set

5 0

3 years ago

Please help me still bad at ratio :)

Sholpan [36]

Answer:

111 grams

Step-by-step explanation:

fruit: yoghurt: total

2 : 3 : 2+3=5

The total mass is 185

Divide 185/5 = 37

Multiply each number by 37

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2*37 : 3 *37 : 5*37

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3 years ago

What’s the transformation

frosja888 [35]

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Step-by-step explanation:

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6 0

3 years ago

(x-2y=-5) (2x + 4y =14) what is the value of y

dusya [7]

Sub x=-5+2y
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6 0

3 years ago

The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?

AleksAgata [21]

Answer:

$\large \boxed{2}$

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

$\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}$

Check:

$\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}$

It checks.

7 0

2 years ago