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VashaNatasha [74]

2 years ago

8

A segment is divided into two parts having lengths in the ratio of 5:3. If the difference between the length of the parts is 6",

find the length of the longest part

2 answers:

aleksley [76]2 years ago

7 0

Answer: the correct answer is 15 I believe.

masha68 [24]2 years ago

5 0

A) x / y = 3 / 5
A) 5x = 3y
A) 5x - 3y = 0
B) y - x = 6
B) 3y -3x = 18
Adding A) and B)
2x = 18
x = 9
y = 15

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You deposit $500 into a savings account that earns 3.2% annual interest. How much is in the savings account after 10 years?

Brilliant_brown [7]

A = P(1 +r/n)^nt
P = 500
r = 3.2% = 0.032
n = 1
t = 10

A = 500(1 + 0.032)^10
A = $685.12

7 0

2 years ago

Which expression represents the inverse of y = 12x - 3

a_sh-v [17]

<span>y = x + 3 / 12
This is your answer.</span>

4 0

2 years ago

Read 2 more answers

Select the correct answer.<br> Solve

Molodets [167]

Answer:

B 1 1/7

Step-by-step explanation:

- 9 2/7 - ( -10 3/7)

We know subtracting a negative is like adding

- 9 2/7 +10 3/7

10 3/7 - 9 2/7

Putting this vertical

10 3/7

-9 2/7

-----------------

1 1/7

5 0

2 years ago

How do u do this please help!!

aev [14]

Answer:

<h2>C. 3 gal. 3 qt. 1 pt.</h2>

Step-by-step explanation:

1 gallon = 4 quarts

5 gallons 2 quarts 1 pint = 4 gallons 6 quarts 1 pint

(5 gallons 2 quarts 1 pint) - (1 gallon 3 quarts)

= (4 gallons 6 quarts 1 pint) - (1 gallon 3 quarts)

= 3 gallons 3 quarts 1 pint

7 0

2 years ago

How to solve the system of equation 500y-600x=2800 , 400y-400x=2400 by elimination

tatiyna

Answer:

$x=2$ and $y=8$

Step-by-step explanation:

Given:

Equation 1:

$500y-600x=2800$

Simplifying the above equation by dividing both sides by 100

$\frac{500y-600x}{100}=\frac{2800}{100}$

$\frac{500y}{100}-\frac{600x}{100}=28\\\\5y-6x=28$

Equation 2:

$400y-400x=2400$

Simplifying the above equation by dividing both sides by 400.

$\frac{400y-400x}{400}=\frac{2400}{400}$

$\frac{400y}{400}-\frac{400x}{400}=6\\\\y-x=6$

Now the system of equation is:

(1a) $5y-6x=28$

(2a) $y-x=6$

Solving by elimination

Multiplying equation (2a) with $-5$

$-5(y-x)=-5\times 6$

(2b) $-5y+5x=-30$

Adding equations (1a) and (2b) in order to eliminate $y$

$5y-6x=28$

+ $-5y+5x=-30$

We get $-x=-2$

∴ $x=2$

Plugging $x=2$ in equation (2a).

$y-2=6$

Adding $2$ both sides.

$y-2+2=6+2$

∴ $y=8$

7 0

2 years ago