Answer:
Step-by-step explanation:
Given that:
To bet $5 that the outcome is any one of these five possibilities: 0, 00, 1, 2, 3.
Let Y represent the Amount of net profit
Then, Y= {-5, 30}
The probability distribution of Y is:
Y -5 30
P(Y=y)

a) The expected value of X is given by:
![E[Y] =\sum y P(Y=y)= 30*\dfrac{5}{38}-5*\dfrac{33}{38}](https://tex.z-dn.net/?f=E%5BY%5D%20%3D%5Csum%20y%20P%28Y%3Dy%29%3D%2030%2A%5Cdfrac%7B5%7D%7B38%7D-5%2A%5Cdfrac%7B33%7D%7B38%7D)


b)
On a bet of $5 on the number 25 we are expected to loose 24 cents.
While on a $5 bet that the outcome is any one of the numbers 0,00, or 1 we are expected to loose 39 cents.
Hence, $5 bet on the number 27 is better. Because the expected loss is less in this bet
Answer:
I think the star just means a variable.
Answer:
I think the answer is (3,10) sorry if I got this wrong!
Step-by-step explanation:
Answer:
x = 2
Step-by-step explanation:
OK so lets do it together.
2x = -2x + 8
Subtract 8 from both sides
2x - 8 = -2x
Add 2x to both sides
4x - 8 = 0
Add 8 to both sides
4x = 8
Divide each side by 4
x = 2
Check:
4 = -4 + 8
4 = 4
correct
If my answer is incorrect, pls correct me!
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-Chetan K