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2 years ago

What values of x satisfy the equation 2x^2 -3x +4 =0

Mathematics

1 answer:

BaLLatris [955]2 years ago

6 0

Answer:

(3 ± √23 * i) /4

Step-by-step explanation:

To solve this, we can apply the Quadratic Equation.

In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)

Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4

Plugging these values into our equation, we get

x = (-b ± √(b²-4ac))/(2a)

x = (-(-3) ± √(3²-4(2)(4)))/(2(2))

= (3 ± √(9-32))/4

= (3 ± √(-23))/4

= (3 ± √23 * i) /4

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2 years ago

Solve for x: two thirds(x − 2) = 4x.

Sveta_85 [38]

Answer:

$x = - 0.4$

Step-by-step explanation:

$\frac{2}{3} (x - 2) = 4x$

Expand with the distributive rule:

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Add 4/3 to both sides:

$\frac{2}{3} x = 4x + \frac{4}{3}$

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5 0

2 years ago

Can someone help me understand this question?

JulijaS [17]

Hey there!

For Part A, because the amount earned on Sunday isn't specified, we can call this additional income x. Because we're writing an expression, we don't need an equal sign. The expression will be (x + 14).

For Part B, "2 less than" will mean "– 2" and "twice than" will mean the amount of dogs that Alicia walked times 2. We can call the amount that Alicia walked y to avoid confusion with the last expression (though you could use whatever variable here) and your expression will be (2y – 2).

Hope this helped you out! :-)

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2 years ago