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ioda
3 years ago
7

Write the standard form of this equation 2x +8+7/2y =0

Mathematics
1 answer:
Crank3 years ago
5 0

Answer:

4x + 7y = -16

Step-by-step explanation:

The standard form of a linear equation is Ax + By = C where A and B cannot be fractions and A is not negative. To write in standard form, clear the denominator by multiplying the equation by 2. Then move the constant to the other side of the equal sign using subtraction.

2x + 8 + 7/2y = 0

2(2x + 8 + 7/2y = 0)

4x + 16 + 7y = 0

4x + 7y = -16

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2. f(x) = 3(x - 2)2 + 6<br>a. Standard Form:​
Alexandra [31]

Answer:

{3x}^{2}   - 4x + 10 = 0

Step-by-step explanation:

3(x - 2) {}^{2}  + 6 \\  3 \times x {}^{2}  - 4x +  {2}^{2}  + 6 \\ 3x {}^{2} - 4x + 4 + 6 \\  {3x}^{2}   - 4x + 10 = 0

6 0
3 years ago
What is the equation in slope-intercept form of a line that has a slope of −12 and a y-intercept of 6?
s2008m [1.1K]

Answer:

y=-12+1

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5 0
3 years ago
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Shtirlitz [24]

Answer:

180-140=50 180-90-50= 40 m=40

3 0
2 years ago
A rectangular enclosure is to be created using 82m rope.
atroni [7]
Let
x-----> the length of rectangle
y-----> the width of rectangle

we know that 
perimeter of rectangle=2*[x+y]
perimeter of rectangle=82 m
82=2*[x+y]---> divide by 2 both sides---> 41=x+y--> y=41-x---> equation 1

Area of rectangle=x*y
substitute equation 1 in the area formula
Area=x*[41-x]----> 41x-x²

using a graph tool
see the attached figure

the vertex is the point (20.5,420.25)
that means
 for x=20.5 m ( length of rectangle)
the area is 420.25 m²

y=420.25/20.5----> 20.5 m

the dimensions are
20.5 m x 20.5 m------> is a square

the answer part 1) 
<span>the dimensions of the rectangular with Maximum area is a square with length side 20.5 meters
</span>
Part 2)<span>b) Suppose 41 barriers each 2m long, are used instead. Can the same area be enclosed?
</span>divide the length side of the square by 2
so
20.5/2=10.25--------> 10 barriers
the dimensions are 10 barriers x 10 barriers
10 barriers=10*2---> 20 m

the area enclosed with barriers is =20*20----> 400 m²

400 m² < 420.25 m²
so

the answer Part 2) is 
<span>the area enclosed by the barriers is less than the area enclosed by the rope
</span>
Part 3)<span>How much more area can be enclosed if the rope is used instead of the barriers
</span>
area using the rope=420.25 m²
area using the barriers=400 m²

420.25-400=20.25 m²

the answer part 3) is
20.25 m²

6 0
3 years ago
Can someone help me with this one
bonufazy [111]

Answer:

x(2x+1)(x-2)

Step-by-step explanation:

x(2x^2-3x-2)

x(2x^2-4x+x-2)

x[2x(x-2)+1(x-2)]

x(2x+1)(x-2)

3 0
3 years ago
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