Answer:
2.92
Step-by-step explanation:
![V=\frac{4}{3}\pi r^3 \\ \\ 105=\frac{4}{3}\pi r^3 \\ \\ r^3=\frac{105}{\frac{4}{3}\pi} \\ \\ r=\sqrt[3]{\frac{105}{\frac{4}{3}\pi}} \\ \\ r \approx 2.92](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%20%5C%5C%20%5C%5C%20105%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%20%5C%5C%20%5C%5C%20r%5E3%3D%5Cfrac%7B105%7D%7B%5Cfrac%7B4%7D%7B3%7D%5Cpi%7D%20%5C%5C%20%5C%5C%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cfrac%7B4%7D%7B3%7D%5Cpi%7D%7D%20%20%5C%5C%20%5C%5C%20r%20%5Capprox%202.92)
Answer:
<em>B. The graph of g is the graph of f shifted 2 units down</em>
Step-by-step explanation:
<u>Graph of Functions</u>
We have two functions:
f(x)=3^x
g(x)=3^x-2
Since g(x)=f(x)-2 it will be represented as an identical graph as that for f(x), but vertically displaced 2 units down. Let's check it by plugging some points
f(0)=3^0=1
g(0)=3^0-2=-1
f(1)=3^1=3
g(1)=3^1-2=1
f(3)=3^3=27
g(3)=3^3-2=25
We can notice the values of g(x) are always 2 units below f(x), thus the correct answer is
B. The graph of g is the graph of f shifted 2 units down
To solve this problem, let us recall that the formula for
probability is:
Probability = total number of successful events / total
events
Where in this case, an event is considered to be successful
if the sum is 3 on the pair of six sided dice.
First, let us calculate for the total number of events. There
are 6 numbers per dice, therefore the total number of combinations is:
total events = 6 * 6 = 36
Next, we calculate for the total number of combinations
that result in a sum of 3. We can identify that there are only two cases that
result in sum of 3. That is:
1st case: first dice rolls 1, second dice
rolls 2
2nd case: first dice rolls 2, second dice
rolls 1
Hence, total number of successful events = 2. Therefore the
probability is:
Probability = 2 / 36 = 1 / 18 = 0.0556 = 5.56%
Answer:
The answer is 13
Step-by-step explanation:
Hope this helps :)
Ain't nobody got time fo dat (drawing number lines)
7 and 1/4=7+1/4
7 and 1/4-3 and 3/4=4 and 1/4-3/4 means
7+1/4-3-3/4=4+1/4-3/4 rearange
7-3+1/4-3/4=4+1/4-3/4
4-2/4=4-2/4
4-1/2=4-1/2
3 and 1/2=3 and 1/2
