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alina1380 [7]
3 years ago
11

Write the fraction 9/50 as a decimal. If necessary, round your answer to the nearest hundredth.

Mathematics
2 answers:
Vadim26 [7]3 years ago
8 0
0.18 is the decimal for 9/50
NikAS [45]3 years ago
7 0
9/50 as a decimal<span> equals </span><span>0.18</span>
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A geometric sequence is defined by the recursive formula t1 = 64, tn = tn - 1 2 , where n ∈N and n &gt; 1. The sequence is
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Answer: The anser is C

Step-by-step explanation: I honestly have no clue but im on usa test prep and guessed but got it right so I figured i'd help someone out lol, gotta go practice

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3 years ago
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In a clinical trial of 268 subjects treated with a​ drug, 11​% of the subjects reported dizziness. The margin of error is plus o
Mariulka [41]

Answer:

\hat p =0.11 represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

\hat q = 1-\hat p = 1-0.11= 0.89 represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

\alpha= 1-0.90 =0.1 and this value represent the significance level of the test or the probability of error type I

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error is given by:

ME= z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Lower= 0.11-0.04 = 0.07

Upper= 0.11+0.04 = 0.15

And for this case we have the following info:

\hat p =0.11 represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

\hat q = 1-\hat p = 1-0.11= 0.89 represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

\alpha= 1-0.90 =0.1 and this value represent the significance level of the test or the probability of error type I

4 0
3 years ago
An agency has 4,000 employees. 2,000 employees have at least two years of college education. 1,000 of those employees have bache
weqwewe [10]

Answer:

1/80 of the agency's employees have PhDs.

Step-by-step explanation:

Given that:

Total number of employees = 4000

Number of employees with bachelors degree = 1000

Fraction of employees with graduate degree = 1/4 of 1000 = 250

1/5 of the employees with graduate degrees have PhD.

Number of employees with PhDs = 1/5 of 250 = 50

Now,

Fraction of PhD employees to total employees = \frac{50}{4000} = \frac{1}{80}

Hence,

1/80 of the agency's employees have PhDs.

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(-4,7) answer A
if u reflect it over y axis
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