Area of triangle = 1/2 x base x height
so old triangle we have 1/2 x b x h = 48
new triangle has base 3 times as long and height is half as long
so we would get:
1/2 x (3B) x (1/2H) = area
rewrite as 1/2 x 3/2 x b x H = area
divide by original are os 1/2 x b x h and you end up with 3/2
so new area = 3/2 x old area
new area = 3/2 * 48 = 72 square inches
Yeah i will dude or dudet ask away
Answer:
x< -0.24
Step-by-step explanation:
So this is going to sound stupid, but I got x< -0.24 which is just not an option, but this is how I got it...
-25x+14>20
subtract 14 from each side
-25x>6
divide each side by -25
x< -0.24
I switch the way the sign was facing bc I divided by a negative.
Now I know that this must be wrong, but it makes the most sense because I am pretty sure I did all of the math right. Sorry this probably didnt help , but I did a lot of work to try and get the right answer, so Im not putting that work to waste
Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
