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lys-0071 [83]
3 years ago
12

What is the scale factor of two regular pentagons with areas of 147 ft.² and 12 ft.²

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0
12.25 is the scale factor if the pre image is 12 and the image is 147
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Combine the like terms to create an equivalent expression: \large{-k-(-8k)}−k−(−8k)minus, k, minus, (, minus, 8, k, )
PIT_PIT [208]

Answer:

7k

Step-by-step explanation:

The given expression is

-k-(-8k)

We need to find the simplified form of the given expression.

Like terms: The terms which have same variables of same degree and known as like terms. For example: 2x and 4x are like terms.

The given expression can be rewritten as

-k+8k

On combining like terms we get

(-1+8)k

7k

Therefore, the equivalent expression of the given expression is 7k.

3 0
4 years ago
Verify the following:<br> 15x(6+(-2) ) = (15x6) + 15x (-2)
NeX [460]

Answer:

-True-

Explanation:

the left side

60

is equal to the right side

60

, which means that the given statement is always true.

6 0
3 years ago
The temperature, T , of a given mass of gas varies inversely with its volume, V . The temperature of a certain gas with volume o
alekssr [168]
We know that

if t<span>he temperature T of a given mass of gas varies inversely with its volume V 
</span>then
T=k/V

Step 1
Find the value of k
for T=30º C and V=105 cm³
we have 
T=k/V--------> k=T*V--------> k=30*105=3150 °C*cm³

therefore
for V=84 cm³
T=3150/84=37.5 °C

the answer is 37.5 °C
3 0
3 years ago
Morgan rewrote the expression 90 + (10 + 4.8) as (90 + 10) + 4.8. How will this change the work that is needed to evaluate the e
serg [7]

Answer:

Answer is c

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
a seed company has a test plot in which it is testing the germination of a hybrid seed, They plant 50 rows of 40 seeds per row.
ziro4ka [17]

Answer:

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

Step-by-step explanation:

x          P(x) x \times P(x)       x^2 \times  P(x)

33         0.02     0.66          21.78

34          0.06     2.04         69.36

35           0.1      3.5        122.5

36           0.2      7.2         259.2

37           0.24     8.88        328.56

38           0.26     9.88        375.44

39            0.1     3.9         152.1

40            0.02     0.8         32

             1        36.86      1360.9

We are supposed to find mean and standard deviation

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

7 0
3 years ago
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