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Montano1993 [528]
3 years ago
7

3 < 5 Add 2 to both sides of the inequality and simplify.

Mathematics
2 answers:
Charra [1.4K]3 years ago
8 0

Answer:

jkshk

Step-by-step explanation:

jdhhkhjkhjjhgghhh

katrin [286]3 years ago
5 0

Step-by-step explanation:

Adding 2 on both sides =

2 + 3 < 5 + 2

6 < 7

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The number of girls in the Middle School Cyber Club was 6 more than double the number of boys, and in total there were 48 middle
Wittaler [7]

Answer:

g = number of girls;

b= number of boys

we know that: g= 6+2b

     and that: g+b= 156 kids in total

so we may write  g+b=(6+2b)+b=6+3b

                 but g+b= 156

so 6+3b = 156 => 3b= 156-6=150 =>   b=150/3=50 => b = 50 (number of boys)

g= 6+2b= 6+2 x 50= 106 => g =106 (number of girls)  

Step-by-step explanation:

5 0
3 years ago
Broooo plzzz helpppp
Sindrei [870]

Answer:

3 3/5 + 1 1/4 = <u>4 17/20</u>

7/8 + 1/12 =<u> 23/24</u>

8/9 - 2/5 = <u>22/45</u>

5 1/4 - 2 2/3 = <u>2 7/12</u>

Step-by-step explanation:

3 3/5 + 1 1/4

First convert into improper fractions

= 18/5 + 5/4

Now find the common denominator

72/20 + 25/20 =

97/20

Now simplify

4 17/20

<u>Next problem:</u>

7/8 + 1/12

find the common denominator

21/24 + 2/24 =

23/24

<u>Next problem:</u>

8/9 - 2/5

find the common denominator

40/45 - 18/45 =

22/45

<u>Next problem:</u>

5 1/4 - 2 2/3

First convert into improper fractions

21/4 - 8/3

find the common denominator

63/12 - 32/12 =

31/12

Now simplify

2 7/12

5 0
3 years ago
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Answer:

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Step-by-step explanation:

5-x<2(x-3)+5

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x>2

7 0
3 years ago
What is the value of x in the eqation 5x+3=4x
Reika [66]

Answer :x=-3

Step-by-step explanation:Solve for  x by simplifying bothh sides of the equation then isoolating the variable

7 0
3 years ago
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A building in a downtown business area casts a shadow that measures 88 meters along the ground. the straight-line distance from
algol [13]
As the building is 88 meters along the around and the shadow makes with a straight line of 32 degrees it would equal 55 meters high.
6 0
3 years ago
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