The two dot plots are missing, so i have attached it.
Answer:
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
Step-by-step explanation:
From the attached image, we are told to compare the means for each plot to the nearest tenth.
Mean = Σx/n
Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;
(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133
Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles
Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143
Mean of miles run at the end of the school year = 143/14 = 10.2 miles
Thus;
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
Answer:
<em>When 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.</em>
Step-by-step explanation:
The Least Common Multiple ( LCM )
The LCM of two integers a,b is the smallest positive integer that is evenly divisible by both a and b.
For example:
LCM(20,8)=40
LCM(35,18)=630
Since Tom, Sam, and Matt are counting drum beats at their own frequency, we must find the least common multiple of all their beats frequency.
Find the LCM of 4,10,12. Follow this procedure:
List prime factorization of all the numbers:
4 = 2*2
10 = 2*5
12 = 2*2*3
Multiply all the factors the greatest times they occur:
LCM=2*2*3*5=60
Thus, when 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.
Answer:
I'm pretty sure it's -3/2
Answer:
x=10
Step-by-step explanation:
hope this helps