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3 years ago

HELPPPPPP MEEEEE!!!!!!

Mathematics

1 answer:

Kazeer [188]3 years ago

3 0

Answer:

It's a

Step-by-step explanation:

The speed goes up, and so does the time

then the speed stays the same but the time keeps going

then the time keeps going and the speed goes down

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In the figure, a ll b and m 6 = 146 degrees <br><br> What is the m 2?

levacccp [35]

Due to m<2 is a corresponding angle to m<6, the answer to the question is 146°.

5 0

3 years ago

At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).

Alekssandra [29.7K]

The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

$\rm F(x)=\dfrac{2}{3x(x-1)(x^ 5)}$

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

$\rm F(x)=\dfrac{2}{3x(x-1)(x^ 5)}$

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

$\rm 3x (x-1) (x^5)= 0$

$\rm x^5 =0, \ \ x=0\\\\ x-1 = 0, \ \ x =1\\$

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

7 0

2 years ago

if traveled a distance of 643 feet how many kilometers did the ball travel? round to the nearest hundredth?

Makovka662 [10]

0.20km is the answer.

Explanation: 1ft = 30.48cm

6 0

3 years ago

Prove that (x-2)is factor of p (x)=2x³-3x²-17x+30

Natasha_Volkova [10]

Answer:

P(2)=0 then x-2 is a factor of P(x)

Step-by-step explanation:

To see if (x-2) is a factor just plug in 2 for x into the polynomial expression.

2(2)^3-3(2)^2-17(2)+30

2(8)-3(4)-34+30

16-12-34+30

4-34+30

-30+30

Since P(2)=0 then x-2 is a factor

8 0

3 years ago

For a Cosine function with amplitude =0.75 and period =10 , what is y(4) ?

frez [133]

We need to find a cosine function:

$y(x)=acos(bx) \\ \\ where: \\ \\ \left|a\right|=Amplitude \\ \\ Period=\frac{2\pi}{b}$

The amplitude represents half the distance between the maximum and minimum values of the function and the period goes from the x-value of one peak to the x-value of the next one. Therefore:

$a=0.75 \\ \\ b=\frac{2\pi}{10}=\frac{\pi}{5}$

Finally:

$\boxed{y(x)=0.75cos(\frac{\pi}{5}x)}$

And y(4) is:

$y(4)=0.75cos(\frac{\pi}{5}\times 4) \\ \\ \therefore \boxed{y(4)=-0.60}$

4 0

3 years ago

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