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lord [1]
3 years ago
11

3 less than a number h is -12

Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:

-9

Step-by-step explanation:

h-3= -12

h= -9

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If f(x) = 2x3 – 12x2 + 26x — 20 and X
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vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
4 years ago
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3 years ago
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5(y+2/5)=-13 <br> need help asap rocky
Gwar [14]

Answer:

y=-3

Step-by-step explanation:

first distribute then solve for y

5y+2=-13

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divide by five on each side

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3 0
3 years ago
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