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faltersainse [42]
3 years ago
8

An angle of measure 150° intersects the unit circle at point (

7B2%7D%2C%20%5Cfrac%7B1%7D%7B2%7D%20%29" id="TexFormula1" title="-\frac{\sqrt{3} }{2}, \frac{1}{2} )" alt="-\frac{\sqrt{3} }{2}, \frac{1}{2} )" align="absmiddle" class="latex-formula">. What is the exact value of cos(150°)?
Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0
So the squat route of three is 9 so 9/2 and then divide which is 4.1
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Rutherfordium- 265 is a radioactive substance that has a half-life of 13 hours. If there is a 149g sample of Rutherfordium- 265
Anna [14]

Answer:

3.21 grams

Step-by-step explanation:

First we are finding the radioactive decay constant using the formula:

lambda = \frac{ln(2)}{half-life}

where

lambda is the radioactive decay constant.

half-life is the half life of the radioactive substance.

We know from our problem that Rutherfordium- 265 has a half-life of 13 hours, so let's replace the value in our formula.

lambda = \frac{ln(2)}{13hours}

lambda = 0.0533 per hour

Now we can use the decay formula to find the remaining quantity of the substance:

N_t=N_0e^{(-lamda)(t)

where

N_t is the ending amount

N_0 is the beginning amount

t is the time (in hours)

We know from our problem that there is a 149g sample of Rutherfordium- 265 left at 12am on October 19th, so N_0=149. Notice that there are exactly 3 days from 12 am October 19th to 12 am October 22nd, so we have 3days(\frac{24hours}{1day} )=72hours; therefore t=72. Now we can replace all the values in our formula:

N_t=149e^{(-0.0533)(72)

N_t=3.21

We can conclude that 3.21 grams of Rutherfordium- 265 would remain on October 22nd at 12 am.

3 0
4 years ago
What is 1 + 2 I really need this answer my grades depend on it!!!
babunello [35]

Answer:

3 is the answer 1 + 2 is the same as 1 + 1 + 1=3

hope this helps

have a good day :)

Step-by-step explanation:

5 0
3 years ago
What is a polyhedron
nataly862011 [7]

Answer: Polyhedron

Step-by-step explanation: A polyhedron is a shape, with 2 parts. Face and Edge, they can only be connected with a edge or a vertex. Only 5 regular polyhedrons exist; tetrahedron ~ 4 faced 'the cube' ~ 6 faced the octahedron ~ 8 faced ~ the dodecahedron ~ 12 faced, and the icosahedron ~ 20 faced.

7 0
3 years ago
I will mark you brainliest once you get the answer correct first!!
Vika [28.1K]

Given:

A composed figure of a rectangle, semicircle and another semicircle removed.

To find:

The area of the given figure.

Solution:

From the given figure it is clear that the diameter of semicircle and removed semicircle are same, i.e. 8 cm.

Since the diameter of semicircle are equal, therefore their area is also equal.

The area of the given figure is:

A = Area of the rectangle - Area of removed semi circle + Area of semicircle

A = Area of the rectangle - Area of semicircle + Area of semicircle

A = Area of the rectangle

We know that, the area of a rectangle is

A=length\times width

The length of the rectangle is 14 units and width is 8 units. So, the area of composed figure is

A=14\times 8

A=112

Therefore, the area of the combined figure is 112 sq. units.

5 0
3 years ago
How do I solve this equation?7n+2=4+17
Artyom0805 [142]

7n + 2 = 4 + 17

7n = -2 + 4 + 17

7n = 19

n = 19/7

your answer is 19/7 (or 2.71)

5 0
3 years ago
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