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2 years ago

How do I convert into pounds

Mathematics

1 answer:

maksim [4K]2 years ago

6 0

The way you convert is by dividing your answer to the question by 1,2or how many they are talking about . Once you do that you will get your answer which may be a decimal and the you put the unit kg for kilograms. so that will be the answer to the problem.

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8x=3(x+1)+2<br><br> What’s x?

Maksim231197 [3]

Answer:

8x=3(x+1)+2 : x =1

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

(Will give Brainliest, these are angle relationships) Please help, and show work, what relationship is it and set up an equation

Vanyuwa [196]

Answer:

Supplementary, 39+5x=180, x=28.2

Step-by-step explanation:

So we know that a straight line is 180 degrees, therefore 52+(5x-13) must equal 180. This is a supplementary relationship. That's our equation, now we just have to solve.

52+5x-13=180

We can straight away combine numbers, giving us

39+5x=180

Now we subtract 39 from both sides, giving us

5x=141.

Now we will answer.

141/5=28.2=x

I'm not sure if this is right, but this is my answer :)

4 0

2 years ago

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A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we

kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

$X_{ij}$ = The number which comes up on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

$E(X_{ij})$ = $\frac {1 + 2 + 3 + 4 + 5 + 6}{6}$

= 3.5 ∀ i = 1(1)10 and j = 1(1)20

and,

$E(X^{2}_{ij}$ = $\frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}$

= $\frac {1 + 4 + 9 + 16 + 25 + 36}{6}$

= $\frac {91}{6}$

$\simeq$ 15.166667

so, $Var(X_{ij}$ = $(E(X^{2}_{ij} - {(E(X_{ij})}^{2})$

$\simeq 15.166667 - 3.5^{2}$

= 2.91667

and $\sigma_{X_{ij}}$ = $\sqrt {2.91667}[/tex [tex]\simeq 1.7078261036$

Now we get that,

$Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}$

We get that $Y_{j}'s$ are iid RV's ∀ j = 1(1)20

Let, ${\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}$

So, we get that $E({\overline}{Y}) = E(Y_{j})$

= $E(X_{ij}$ for any i = 1(1)10

= 3.5

and,

$\sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}} = \frac {\sigma_{X_{ij}}}{\sqrt {20}} = \frac {1.7078261036}{\sqrt {20}} [tex]\simeq 0.38$

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

6 0

3 years ago

A forester planted 3 acres in seedlings the first day, 5 acres the second day, and

Yanka [14]

Answer:

9 acres remain

Step-by-step explanation:

First day:

3 acres

Second day:

5 acres were planted. 5 + 3 = 8

Third day:

4 acres were planted. 4 + 8 = 12

If 3 acres were destroyed, we just subtract!

12 - 3 = 9.

9 acres of seedlings remain.

I hope this helped! :)

6 0

3 years ago

Kena calculates that she spends 15% of a school day in science class. If she spends 75 minutes in science class, how many minute

ankoles [38]

Answer:

Step-by-step explanation:

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2 years ago