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bija089 [108]
3 years ago
9

Hurry up pls!!! i need some help quick fast plssss!!!!

Mathematics
1 answer:
inna [77]3 years ago
8 0

Answer:

45

Step-by-step explanation:

9 x 5 = 45

it's a multiplication question

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Hillsdale's zoo has two elephants. The male elephant weighs 9 7/12 tons and the female elephant weighs 3 5/6 tons. How much more
Alex Ar [27]

Answer:

6 10/12

Step-by-step explanation:

thank u

7 0
2 years ago
Read 2 more answers
2/3 + 5/6 in the simplest form
asambeis [7]
Here is your answer:

2×2=4
3×2=6
+
5×1=5
6×1=6

4+5=9

9÷3=3
6÷3=2

Your answer is...
=3/2
6 0
3 years ago
Each week Danny eats 540 grams of cereal over 8 weeks. He finishes a total of 12 boxes of cereal. Each box contains the same amo
leonid [27]

Answer:

360 grams of cereal

Step-by-step explanation:

First you have to do 540 times 8 to find out how many grams of cereal he ate over the eight weeks.

Then you have to divide the answer by 12 to get 360 grams of cereal.

I hope this helped ;)

8 0
3 years ago
0.4(x-0.45)=9.2 PLZZZZZ HELP!!!!!!!
Helen [10]

Answer:

0.4(−0.45)=9.2

2(−0.45)5=9.2

Step-by-step explanation:

=23.45

5 0
2 years ago
given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ
rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0
3 years ago
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