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3 years ago

Hurry up pls!!! i need some help quick fast plssss!!!!

Mathematics

1 answer:

inna [77]3 years ago

8 0

Answer:

Step-by-step explanation:

9 x 5 = 45

it's a multiplication question

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Which is greater 6/11 or 5/9 or are they equal?

lutik1710 [3]

Answer:

5/9

Step-by-step explanation:

6/11 is 0.54545454545

5/9 is 0.5555555556

8 0

3 years ago

Read 2 more answers

Please help me with this math problem

kari74 [83]

It’s the graph with points (0,0)

6 0

3 years ago

A rhinoceros weight when rounded to the nearest thousand was 4,000 pounds. Which of these is the least the rhinoceros could have

Rudik [331]

Answer:

B- 3,500.

Step-by-step explanation:

This is because 3,500 is the lowest number that can be rounded to 4,000.

3,999 and 4,001 can also be rounded but.. (let me show you an image to help).

3,500 < 3,999 < 4,001.

That goes from smallest to largest numbers that round to 4,000.

Hope that helps. x

5 0

3 years ago

Each algorithm is applied to a group of 52 sample problems. The new algorithm completes the sample problems with a mean time of

dem82 [27]

Answer:

Therefore we fail to reject the Null hypothesis $H_0$

Because the is no sufficient evidence to support the claim of the alternative hypothesis $H_a$

Step-by-step explanation:

From the question we are told that

Sample size $n_1 =52$

Mean time 1 $\=x_1=24.04\ hours$

Mean time 2 $\=x_2=24.52\ hours$

Standard deviation $\partial _1=5.769$

Standard deviation $\partial _2=5.556$

Level of significance 0.05

The null hypothesis is $H_o: \mu_1=\mu_2$

Alternative hypothesis $H_a: \mu_1$

Generally the test statistics is mathematically represented as

$Z= \frac{\=x_1-\=x_2}{\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}}$

$Z= \frac{24.04-24.52}{\sqrt{\frac{5.769^2}{52}+\frac{5.5562^2}{52}}}$

$Z= -0.4321583379$

$Z= -0.43$

From Table the Z-critical value at $\alpha =0.05\ is\ -1.6449$

Therefore

Zcal> Zcritical

(-0.43)=(-1.645)

Generally we fail to reject the null hypothesis $H_0$ at $\alpha = 0.05$

Therefore we fail to reject the $H_0$

Because the is no sufficient evidence to support the claim of $H_a$

5 0

3 years ago

7. AstudyoftheannualnumberofbreedingpairsofBaldEaglesinMichiganfrom1990-2006,showsthenumberofpairs, E(t), can be represented by

soldier1979 [14.2K]

Well, the give us 1990-2006 as the time period. If you don't know how many years that is and don't feel like counting: 2006-1990=16

Then plug it in the equation t=16
E(t)=204(1.04)t
E(16)=204(1.04)16
E(16)=212.16•16
E(16)=3394.46

6 0

4 years ago