8 1/2 times 120 times 20 3/10 = 20706
L*W*H
Hope this helps :D
You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
You would Not have to regroup for this problem
Answer: C
Step-by-step explanation:
You can solve this by first multiplying both sides of the fraction by the conjugate of the denominator.
In this case, the conjugate is (8 - 2i).
So:
Simplify:
Simplify again, knowing that i^2 = -1
Then, divide both numbers in the numerator by 68 to get your answer.
