All categories

3 years ago

Kaitien paid $71.50 for 5 movies tickets. What was the price of each ticket?

Mathematics

1 answer:

kondaur [170]3 years ago

5 0

Answer:

14.3

Step-by-step explanation:

$71.50 for 5 tickets

71.50 ÷ 5 = 14.3 there's no need to round the result.

You might be interested in

Use the following data set to answer numbers 1 - 4.

alukav5142 [94]

Answer:

1. 13+18+13+14+13+16+14+21+13

= 145/9

=16.11

2. Range =145

3. Mode =13

4. Median =14

Step-by-step explanation:

6 0

2 years ago

Which statement best describes the effect on the graph of y = (x – 9)2 if the equation is changed to y = (x + 9)2?

7nadin3 [17]

Answer:

You won't be in the negative but postive side of the graph

Step-by-step explanation:

6 0

3 years ago

A company now has 4500 employees nationwide. It wishes to reduce the number of employees by 250 per year through retirements un

Darya [45]

4500 - 2300 = 2200

They wish to get rid of 2200 employees

250(x) = 2200

Divide 2200 by 250

x = 8.8

It will take 8.8 years.

6 0

3 years ago

Please can someone help me. Work is due tomorrow . Show your work and good luck.:)

jolli1 [7]

One third. pam put two thirds into the bowl. so... cole put one third into the bowl. one third was put into the bowl by cole. Hope that helps = )

7 0

3 years ago

Read 2 more answers

if Dakota earned $15.75 in interest in account A and $28.00 in interest in account B after 21 months. if the simple interest rat

NISA [10]

keeping in mind that 21 months is more than a year, since there are 12 months in a year, then 21 months is really 21/12 years.

$\bf ~~~~~~ \stackrel{\textit{account A}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &15.75\\ P=\textit{original amount deposited}\dotfill \\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\to \frac{21}{12}\dotfill &\frac{7}{4} \end{cases} \\\\\\ 15.75=P(0.03)\left( \frac{7}{4} \right)\implies \cfrac{15.75}{(0.03)\left( \frac{7}{4} \right)}=P\implies \boxed{300=P}$

$\bf ~~~~~~ \stackrel{\textit{account B}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &28\\ P=\textit{original amount deposited}\dotfill \\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ t=years\to \frac{21}{12}\dotfill &\frac{7}{4} \end{cases} \\\\\\ 28=P(0.049)\left( \frac{7}{4} \right)\implies \cfrac{28}{(0.049)\left( \frac{7}{4} \right)}=P\implies \boxed{326.53\approx P}$

so, clearly, you can see who's greater.

3 0

3 years ago