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elena55 [62]
3 years ago
9

Skill 3 prime factorization

Mathematics
1 answer:
slega [8]3 years ago
6 0

Explanation:

Prime factorization says that, if a number is prime then the only way it can be factored is, 1 times the number itself.

But if the number is composite, it can be expressed as a product of prime factors. This method is called prime factorization.

For example: 12 is a composite number, it can be written in the form of prime factorization as,

12 = 2 \times 2 \times 3

Here we can see that 12 is expressed as the product of primes only. This is called prime factorization.  

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Twenty-five samples of 100 items each were inspected when a process was considered to be operating satisfactorily. In the 25 sam
notsponge [240]

a) The estimate of the proportion of defectives when the process is in control is 0.054

b) The standard error of the proportion if the sample size is 100 is 0.0226.

c) The upper control limit is 0.1218 and the lower control limit is 0 (since LCL < 0 and p > 0, we can write LCL = 0).

<h3>What are the formulas for finding the estimate of the proportion, standard variation, and control limits?</h3>

1) The estimate of the proportion of success is

p = (number of success)/(total number of samples)

I.e., p = x/N

2) The standard deviation of the proportion of success is

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3) The upper and lower control limits for a control chart are:

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<h3>Calculation:</h3>

It is given that, there are 25 samples of 100 items each.

So, the total number of items i.e., the total sample size,

N = 25 × 100 = 2500

In 25 samples, a total of 135 items were found to be defective.

So, the number of defectives x = 135

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On substituting, we get

p = 135/2500 = 0.054

b) The standard error of the proportion if the sample of size 100 is calculated by

\sigma_p = \sqrt{\frac{p(1-p)}{n} }

On substituting p = 0.054 and  n = 100, we get

\sigma_p = \sqrt{\frac{0.054(1-0.54)}{100} }

    = 0.0226

c) The control limits for the control chart are:

Upper control limit =  p + 3\sigma_p

⇒ U.C.L = 0.054 + 3(0.0226) = 0.054 + 0.0678 = 0.1218

Lower control limit = p - 3\sigma_p

⇒ L.C.L = 0.054 - 3(0.0226) = 0.054 - 0.0678 = - 0.0138 ≈ 0

(Since we know that the lower control limit should not be a negative value, it is made equal to 0).

Learn more about an estimate of the proportion here:

brainly.com/question/23986522

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