Answer:
The value of basketball player's autograph a year ago is $280
Step-by-step explanation:
Given as :
The present value of autograph = $ 336.00
The rate of increase of autograph = 20%
The time period = 1 year
Let The value one year ago = $ x
So ,
The value of autograph after n year = The present value × 
Or, $ 336.00 = $ x × 
Or, $ 336.00 = $x × 1.2
∴ x = 
= $280
Hence The value of basketball player's autograph a year ago is $280 Answer
Given:
Cost of one pound of apples = $1.98
To find:
The cost of 0.75 pound of apples.
Solution:
We have,
Cost of one pound = $1.98
So, cost of 0.75 pound of apples = 0.75 × cost of one pound of apples
Therefore, the cost of 0.75 pound of apples is $1.485.
Answer:
The answer is A
Step-by-step explanation:
domain is always the x-value and range is a y-value
(Correct me if i am wrong)
Answer:
B
Step-by-step explanation:
Answer:
2x²y+(x²y-2xy²) = 3x²y-2xy²
(5xy²-x²y) +3x²y = 5xy²-2x²y
4x²y+(x²y+xy²) = 5x²y+xy²
x²y+(-2xy²-4x²y) = -3x²y-2xy²
Step-by-step explanation: there you go
