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hammer [34]
3 years ago
13

As we study random variables, the idea of z-scores will come up again. What is a z-score (in words) and what is the formula for

finding a z-score?
Mathematics
1 answer:
arsen [322]3 years ago
7 0
For a confidence interval with level C, the value p is equal to (1-C)/2. A 95% confidence interval for the standard normal distribution, then, is the interval (-1.96,1.96), since 95% of the area under the curve falls within this interval. <span>The point estimate for the </span>population proportion<span> is the sample proportion, and the margin of error is the product of the Z value for the desired confidence level (e.g., Z=1.96 for </span>95%<span> confidence) and the standard error of the point </span>
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22.29% probability that both of them scored above a 1520

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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\mu = 1497, \sigma = 322

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.

So

Z = \frac{X - \mu}{\sigma}

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Z = 0.07

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1 - 0.5279 = 0.4721

Each students has a 0.4721 probability of scoring above 1520.

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