Answer:
In times past, gathering information on a potential partner in marriage or business routinely started with the simplest question “What family does he or she come from?” Affiliation with a certain family immediately provided a starting point for further inquiries, a general idea of what might be expected from a certain individual. Of course, families are never uniform, and classic literature from Homer to Shakespeare to Tolstoy provides ample illustrations that any expectation based solely on family history should be taken with a grain of salt. Nevertheless, in the absence of other clues to the character of the subject in question, an educated guess could be made based on the family structure and the individual’s position within that structure
Explanation:
According to Lavoisier's law, in the given reaction the mass of zinc produced will be 104 g.
Let's consider the following reaction.
Ca + ZnCO₃ ⇒ CaCO₃ + Zn
64g 192 g 152 g ? g
<h3>What does Lavoisier's law state?</h3>
Lavoisier's law states that the sum of the masses of the reactants before the reaction is equal to the sum of the masses of the products after the reaction.
mCa + mZnCO₃ = mCaCO₃ + mZn
mZn = mCa + mZnCO₃ - mCaCO₃
mZn = 64 g + 192 g - 152 g = 104 g
What would be the amount of zinc formed during the reaction?
- The mass of zinc produced will be 104 g. TRUE.
- The mass of zinc will be the same as that of zinc carbonate. FALSE.
- The mass of zinc produced will be 52 g. FALSE.
- The mass of zinc will be the same as that of calcium. FALSE.
According to Lavoisier's law, in the given reaction the mass of zinc produced will be 104 g.
Learn more about Lavoisier's law here: brainly.com/question/11429078
Answer:
C. 99.9% positive
Explanation:Hope this Helps :)
If each subunit of a hemoglobin protein molecule carries a heme group and a hemoglobin protein molecule is made of four subunits, two α and two β, we can simply multiply four (number of heme groups that can be found in one hemoglobin protein molecule) by three (number of hemoglobin protein molecules considered). 4×3=12
There are twelve heme groups in three hemoglobin protein molecules.
Your answer is going to be D