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Gala2k [10]
3 years ago
15

Help me solve this Algebra problem please​

Mathematics
1 answer:
sp2606 [1]3 years ago
4 0

Answer:

39858075

Step-by-step explanation:

Hello,

One basic way to see it is to compute the values.

   75 = 25 * 3

   225 = 75 * 3

   675 = 225 * 3

   etc ...

We can notice that this is multiplied by 3 every 10 years so we can compute as below.

year         population

1970 25

1980 75

1990 225

2000 675

2010 2025

2020 6075

2030 18225

2040 54675

2050 164025

2060 492075

2070 1476225

2080 4428675

2090 13286025

2100 39858075

So the correct answer is 39858075

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Find the value of X(2x + 4) (2x-9)
kotykmax [81]

2x +4)° 2x-9)°= 4x  2 +8x−9=3

 Pull out like factors :

  2x + 4  =   2 • (x + 2) (4 • (x + 2) • x) -  9

4x • (x + 2) -  9

Factoring  4x2+8x-9  

The first term is,  4x2  its coefficient is  4 .

The middle term is,  +8x  its coefficient is  8 .

The last term, "the constant", is  -9  

Step-1 : Multiply the coefficient of the first term by the constant   4 • -9 = -36  

Step-2 : Find two factors of  -36  whose sum equals the coefficient of the middle term, which is   8 .

     -36    +    1    =    -35  

     -18    +    2    =    -16  

     -12    +    3    =    -9  

     -9    +    4    =    -5  

     -6    +    6    =    0  

     -4    +    9    =    5  

     -3    +    12    =    9  

     -2    +    18    =    16  

     -1    +    36    =    35

x=3

6 0
3 years ago
Read 2 more answers
If f(x) = 8x2 + 4x - 12. Find f(2)<br> f(2)=
posledela

Answer:

f(2) = 28

Step-by-step explanation:

\rm f(x) = 8 {x}^{2}  + 4x - 12

\rm Evaluate \:  8 x^2 + 4 x - 12 \:  where  \: x = 2: \\  \\  \rm \implies f(2) = 8 \times {2}^{2}  + 4 \times 2 - 12 \\  \\   \rm \implies f(2) = 8 \times 4 + 8 - 12 \\  \\   \rm \implies f(2) = 32 - 4 \\  \\   \rm \implies f(2) = 28

3 0
2 years ago
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
3 years ago
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lord [1]

Answer:

The denominators are not equal.

Step-by-step explanation:

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2 years ago
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Answer:

Step-by-step explanation:

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504  : x

x=540x100/90

x=50400/90

x=560

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