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mash [69]
4 years ago
5

juggles the clown stands on one end of a teeter-totter at rest on the ground. Bangles the clown jumps off a platform 2.4 m above

the ground and lands on the other end of the teeter-totter, launching Juggles into the air. Juggles rises to a height of 3.2 m above the ground, at which point he has the same amount of gravitational potential energy as Bangles had before he jumped, assuming both potential energies are measured using the ground as the reference level. Bangles' mass is 75 kg. What is Juggles' mass
Physics
1 answer:
andre [41]4 years ago
8 0

Answer:

m_{j}=56.25kg

Explanation:

Given data

Bangles mass m_{B}=75kg his height before jump is h_{B}=2.4m and final height of juggles is h_{j}=3.2m

First we need to get gravitational potential energy of Bangles before he jumps

PE_{B}=m_{B}*g*h_{B}\\PE_{B}=(75kg)(9.8m/s^2)(2.4m)\\PE_{B}=1764J

Since the gravitational potential energy of Bangles before he jumps equals to gravitational potential energy of Juggles at his final height

So

PE_{j}=PE_{B}\\m_{j}*g*h_{j}=1764J\\m_{j}*(9.8m/s^2)(3.2m)=1764J\\m_{j}*31.36=1764\\m_{j}=1764/31.36\\m_{j}=56.25kg  

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3 years ago
A parallel-plate air capacitor is made from two plates 0.210 m square, spaced 0.815 cm apart. it is connected to a 120 v battery
GuDViN [60]

Answer:

at the beginning: 2.3\cdot 10^{-10} F

when the plates are pulled apart: 1.1\cdot 10^{-10} F

Explanation:

The capacitance of a parallel-plate capacitor is given by

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A=0.210 m^2 is the area of the plates

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Substituting into the formula, we find

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Later, the plates are pulled apart to d=1.63 cm=0.0163 m, so the capacitance becomes

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Answer:

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