Question

juggles the clown stands on one end of a teeter-totter at rest on the ground. Bangles the clown jumps off a platform 2.4 m above the ground and lands on the other end of the teeter-totter, launching Juggles into the air. Juggles rises to a height of 3.2 m above the ground, at which point he has the same amount of gravitational potential energy as Bangles had before he jumped, assuming both potential energies are measured using the ground as the reference level. Bangles' mass is 75 kg. What is Juggles' mass

Answer 1

Answer:

$m_{j}=56.25kg$

Explanation:

Given data

Bangles mass $m_{B}=75kg$ his height before jump is $h_{B}=2.4m$ and final height of juggles is $h_{j}=3.2m$

First we need to get gravitational potential energy of Bangles before he jumps

$PE_{B}=m_{B}*g*h_{B}\\PE_{B}=(75kg)(9.8m/s^2)(2.4m)\\PE_{B}=1764J$

Since the gravitational potential energy of Bangles before he jumps equals to gravitational potential energy of Juggles at his final height

So

$PE_{j}=PE_{B}\\m_{j}*g*h_{j}=1764J\\m_{j}*(9.8m/s^2)(3.2m)=1764J\\m_{j}*31.36=1764\\m_{j}=1764/31.36\\m_{j}=56.25kg$