Question

Determine the moment of inertia of a uniform solid sphere of mass M and radius R about an axis that is tangent to the surface of the sphere. (Use any variable or symbol stated above as necessary.)

Answer 1

Answer:

$I = \frac{7}{5}MR^2$

Explanation:

For answer this we will use the paralell axis theorem:

I= $I_{cm} + Md^2$

Where $I_{cm}$ is the moment of inertia of the center of mass, M is the mass of the sphere and d is the distance between the center of mass and the axis for rotate, then:

$I = \frac{2}{5}MR^2 +MR^2$

$I = \frac{7}{5}MR^2$